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rjkz [21]
2 years ago
13

which of these releases heat a. melting candle wax b.boiling water to make stem c. burning wood in a campfire d. making popcorn

over a fire
Chemistry
1 answer:
zvonat [6]2 years ago
8 0

c. burning wood in a campfire

Explanation:

Wood burning in a campfire is an exothermic process.

An exothermic reaction is one in which heat is liberated to the surroundings. The heat content of the reactants is greater than that of the products.

Every burning process is an exothermic reaction.

An exothermic reaction liberates heat to the surrounding.

Other option given takes heat from the surrounding.

learn more:

Exothermic process brainly.com/question/10567109

#learnwithBrainly

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A weather balloon was initially at a pressure of 0.900 atm, and its volume was 35.0 L. The pressure decreased to 0.750 atm, with
marusya05 [52]

Boyle's Law

P₁V₁=P₂V₂

0.9 x 35 = 0.75 x V₂

V₂ = 42 L

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The hypothetical elements shown here (figures a–d) do not include hydrogen or helium. Which element would you expect to bond cov
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A sample of gas is observed to effuse through a pourous barrier in 4.98 minutes. Under the same conditions, the same number of m
kogti [31]

Answer:

The molar mass of the unknown gas is \mathbf{ 51.865 \  g/mol}

Explanation:

Let assume that  the gas is  O2 gas

O2 gas is to effuse through a porous barrier in time t₁ = 4.98 minutes.

Under the same conditions;

the same number of moles of an unknown gas requires  time t₂  =  6.34 minutes to effuse through the same barrier.

From Graham's Law of Diffusion;

Graham's Law of Diffusion states that, at a constant temperature and pressure; the rate of diffusion of a gas is inversely proportional to the square root of its density.

i.e

R \  \alpha  \ \dfrac{1}{\sqrt{d}}

R = \dfrac{k}{d}  where K = constant

If we compare the rate o diffusion of two gases;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{d_2}{d_1}}

Since the density of a gas d is proportional to its relative molecular mass M. Then;

\dfrac{R_1}{R_2}= {\sqrt{\dfrac{M_2}{M_1}}

Rate is the reciprocal of time ; i.e

R = \dfrac{1}{t}

Thus; replacing the value of R into the above previous equation;we have:

\dfrac{R_1}{R_2}={\dfrac{t_2}{t_1}}

We can equally say:

{\dfrac{t_2}{t_1}}=  {\sqrt{\dfrac{M_2}{M_1}}

{\dfrac{6.34}{4.98}}=  {\sqrt{\dfrac{M_2}{32}}

M_2 = 32 \times ( \dfrac{6.34}{4.98})^2

M_2 = 32 \times ( 1.273092369)^2

M_2 = 32 \times 1.62076418

\mathbf{M_2 = 51.865 \  g/mol}

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Explanation:

Specific heat capacity is how much is required to heat the unit of mass by one degree. Therefore, if you have a higher heat capacity it required more energy, therefore, it takes longer to heat up. whereas having a lower heat capacity it takes less time to best up as it requires less energy.

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How many acetyl coa molecules may be obtained from oxidation of an 18-carbon fatty acid?
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