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ivolga24 [154]
3 years ago
6

After water What is the most important materials in cells

Chemistry
2 answers:
Lynna [10]3 years ago
8 0
All cells need oxygen for respiration. It is the process of respiration that releases the energy needed for the cell's activities. Also needed for respiration is glucose, the substance that is broken down to release energy.
Artist 52 [7]3 years ago
5 0

Answer:

air

Explanation:

air gives as life.hhhhh&hhhhhhhhhhhhhhhhhhh

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Help ASAAPPPPPPPPPP!!!!
Verdich [7]
Third choice is correct. 
6 0
3 years ago
Describe how you would obtain a beaker of pure water from salty water
Maslowich

Answer:

You can boil or evaporate the water and the salt will be left behind as a solid. If you want to collect the water, you can use distillation. This works because salt has a much higher boiling point than water. One way to separate salt and water at home is to boil the salt water in a pot with a lid.

Explanation:

4 0
3 years ago
I just need help with question 10.??? Please ASAP
Alex

Answer:

4 hydrogen / 1 Carbon

Just look at the diagram

4 0
3 years ago
How many moles of h2o are produced when 3.25 moles of o2 react in 2c2h6 + 7o2 ---> 4co2 + 6h2o
Alenkinab [10]

Answer:

2.78 moles of water are produced.

Explanation:

Given data:

Number of moles of H₂O produced = ?

Number of moles of oxygen react = 3.25 mol

Solution:

Chemical equation:

2C₂H₆ + 7O₂       →     4CO₂ + 6H₂O

Now we will compare the moles of water with oxygen.

                O₂          :          H₂O

                 7            :           6

               3.25        :           6/7×3.25 = 2.78 mol

5 0
3 years ago
Calculate the molar concentration of the polycyclic aromatic hydrocarbon (pah), anthracene (178.23 g/mol), that was found in a w
tester [92]

solution:

Calculate the molar concentration of the polycyclic aromatic hydrocarbon(PHA)(178.23g/mol),that was found in a well water sample at a concentration of 6.21ppb.Assume the density of the water is 1.00mg/mLppb corresponds to 1\mu g in 1L of sample \\the 6.21 ppb is 6.21\mu g in 1L of sample\\6.21\mu g PHA\times\frac{1mg PHA}{1000\mu g PHA}\times\frac{1g PHA}{1000\mu mg PHA}\times\frac{1mol. PHA}{178.23g PHA}\\3.48\times10^-8mol PHA\\and if we have 1L of solution\\m=\frac{moles}{v(L)}=\frac{3.48\times10^-8mol}{1L}\\3.348\times^10-8 M

3 0
3 years ago
Read 2 more answers
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