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Ede4ka [16]
2 years ago
11

What is the total number of mole of atoms in 1 mol of Cu(NO3)2 ?*

Chemistry
1 answer:
Ulleksa [173]2 years ago
3 0

actually kiska total number nikalna h. cu(no3)2.

your question are not completely.

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Be sure to answer all parts. For each of the following pairs of elements, state whether the binary compound they form is likely
andrew-mc [135]

Answer:

(a) Covalent bond. NF₃ (nitrogen trifluoride)

(b) Ionic bond. LiCl (lithium chloride)

Explanation:

<em>(a) N and F</em>

Nitrogen and fluorine are nonmetals, with high and similar electronegativities, so they form covalent bonds, in which they share pairs of electrons to complete the octet in their valence shell. N has 5 valence electrons so it will form 3 covalent bonds while each Cl has 7 valence electrons so it will form 1 covalent bond. As a result, the empirical formula is NF₃ (nitrogen trifluoride).

<em>(b) Li and Cl</em>

Lithium is a metal and Chlorine is a nonmetal. They have different electronegativities so they form an ionic bond, in which Cl gains 1 electron (7 valence e⁻) and Li loses 1 electron (1 valence e⁻). The empirical formula is LiCl (lithium chloride).

5 0
3 years ago
Which best describes nuclear fission? A nucleus spontaneously splits and absorbs energy. Two nuclei spontaneously combine and ab
Maurinko [17]

Answer:

A nucleus collides with a neutron and splits, releasing energy.

Explanation:

5 0
2 years ago
Read 2 more answers
What is the percent composition of each of the elements in Al(OH) 3 ?
stellarik [79]

Answer:

<em>Answer Below</em>

Explanation:

Percent composition by element

<u>Element </u>       <u>Symbol</u>  <u>Mass Percent</u>

Aluminium <u>Al</u>          34.590%

Hydrogen <u>H</u>          3.877%

Oxygen         <u>O</u>          61.533%

3 0
3 years ago
Read 2 more answers
I don’t understand this question and need help!!
Dafna1 [17]
Medium about 3 second? Not sure lol just need more points honestly lol
6 0
2 years ago
What is the total probability of finding a particle in a one-dimensional box in level n = 4 between x = 0 and x = L/8?
Lubov Fominskaja [6]

Answer:

P = 1/8

Explanation:

The wave function of a particle in a one-dimensional box is given by:

\psi = \sqrt \frac{2}{L} sin(\frac{n \pi x}{L})

Hence, the probability of finding the particle in the  one-dimensional box is:

P = \int_{x_{1}}^{x_{2}} \psi^{2} dx

P = \int_{x_{1}}^{x_{2}} (\sqrt \frac{2}{L} sin(\frac{n \pi x}{L}))^{2} dx

P = \frac{2}{L} \int_{x_{1}}^{x_{2}} (sin^{2}(\frac{n \pi x}{L}) dx

Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:

P = \frac{2}{L} [\frac{L}{16} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})]

P = \frac{1}{8} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})    

Solving for n=4:

P = \frac{1}{8} (1 - 4\frac{sin(\frac{4 \pi}{4})}{4 \pi})    

P = \frac{1}{8} (1 - \frac{sin (\pi)}{\pi})    

P = \frac{1}{8}

I hope it helps you!

7 0
3 years ago
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