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X=13+4x. 13+4x=22
0=13+3x. 4x=9
3x=-13. x=9/4
x=13/3
16 bc all sides of a square are congruent and area = LxW so 4x4=16
F twice the 1st number minus 3 times the second number is 26<span>, </span>find both<span> ... </span>Twice the first number<span> is eleven more than </span>the sum<span> of the other </span>two numbers<span>.</span>
Answer:
B 3x+2
Step-by-step explanation:
perimiter=2L+2W
P=2(L+W)
if x=width then
P=2(L+x)
P=8x+8
hmm
8x+8=2(L+x)
distribute
8x+8=2L+2x
minus 2x both sides
6x+8=2L
divide both sides by 2
3x+4=L
the length is 3x+4
B is answer