1.What is the first quartile of these numbers?

Classify each triangle write acute,right or obtuse

svetlana [45]

They were all right except for:
angle G is a right angle
3. Is an obtuse
4. is an acute
(I couldn't see #7)
and the answer for the last question is the equilateral in the middle

8 0

3 years ago

Read 2 more answers

At Ree Ski Center, the most people will pay for a neck warmer is $10. The manager of Ree Ski Center knows he needs a 30% markup

taurus [48]

Let $x$ be the most the manager can pay the suppliers.

Then, we know from the information given in the question that the manager needs a 30% markup based on cost.

Therefore, the guiding equation will be:

$x+\frac{30}{100}x\leq 10$

because $10 is the most people will pay for a neck warmer.

Thus, the above equation will become:

$x+0.3x\leq 10$

$1.3x\leq 10$

$x\leq \frac{10}{1.3}=7.69$

$\therefore x\leq 7.69$

Thus, the most a manager can pay the suppliers for neck warmers and still keep the selling price at $10 is $7.69

4 0

4 years ago

Evaluate each expression<br> 6! =<br> 3! • 2=<br> 31

Airida [17]

<h2><u>N-FACTORIAL!</u></h2>

<h3> $\mathbb{ \color{brown} \: PROBLEM } \: \: \bold{{ \color{brown}{1}}} :$ </h3>

$\mathcal{SOLUTION: }$

$\: \bold{ \red{6!}= 6×5×4×3×2×1= \boxed{ \bold{ \blue{720}}}}$

Therefore, <u>the value of 6! is 720</u>.

━┈─────────────────────┈━

<h3> $\mathbb{ \color{brown} \: PROBLEM } \: \: \bold{{ \color{brown}{2}}} :$ </h3>

$\mathcal{SOLUTION: }$

$\bold{3! \cdot 2! }\implies \bold{(3×2×1) \cdot( 2×1 )}$

$\: \: \: \: \: \: \: \: \: \: \: \: \implies \: \bold{ 6 \times 2} = \boxed{ \bold{ \blue{12}}}$

Therefore, <u>the value of the given expression is 12.</u>

━┈─────────────────────┈━

<h3><u>EXPLANATION</u><u>:</u></h3>

The mathematical symbol n! is read as "n factorial". The exclamation point "!" is read as factorial. And please remember or take note that 0! is equal to 1, and 1! is also equal to 1.

_______________∞_______________

6 0

2 years ago

Please help me with this

Llana [10]

4 unknowns needs 4 equations. I'll call the unknown numbers a,b,c,d in that order left to right.

4 + a = b
a + b = c
b + c = d
c + d = 67

let's use substitution to get rid to combine equations and get rid of variables.
If a + b = c then a = c - b
4 + (c - b) = b
4 + c = 2b

If b + c = d then b = d - c
4 + c = 2(d - c)
4 + c = 2d - 2c
4 + 3c = 2d

then we have c + d = 67 so c = 67 - d

4 + 3(67 - d) = 2d
4 + 201 - 3d = 2d
205 = 5d
d = 41

Should be easy now, subtract backwards.

67 - 41 = 26
41 - 26 = 15
26 - 15 = 11
15 - 11 = 4

4, 11, 15, 26, 41, 67

3 0

3 years ago

Plzzz Solve these 7 Questions ASAP !!<br> PLZZZZZZZZZZZ IT'S A REQUEST !!!

e-lub [12.9K]

Answer:

B is an answer.

6 0

3 years ago