To determine whether a solution a set of a system of linear inequalities is right, you simply plug back into the equation to check your work. If the solution equals and is mathematically correct, then that's the answer. For Example, use the equation,
5x = 10
Let's say you got an answer of x = 4. Plug it back into the equation
5(4) ≠ 10. As you can see the answer is wrong. This shows you that the answer is wrong.
The correct answer is x = 2
Answer:
1.) It's 20th century painting
2.) 0.5 probability
Step-by-step explanation:
If the universal = 60
We need to first get the value of X. That is,
x (x - 2) + x + 2x + 8 + 10 = 60
First open the bracket
x^2 - 2x + x + 2x + 8 + 10 = 60
x^2 + x + 18 = 60
x^2 + x - 42 = 0
Factorise the above equation
x^2 + 7x - 6x - 42 = 0
x (x + 7) -6(x + 7) = 0
x = 6 or - 7
Since x can't be negative, so we will ignore -7
The value for T = 6(6 - 2) = 6×4 = 24
The value for B = 2(6) + 8 = 12 + 8 = 20
If a painting is chosen from random,
If it's from 20th century, the probability will be 34/60 = 0.567
If it's from British painting, the probability will be 30/60 = 0.5
We can therefore conclude that it's from 20th century painting since it has higher value of probability.
The the probability of choosing a British painting will be 30/60 = 0.5
-- All of the non-zero digits are: 1, 2, 3, 4, 5, 6, 7, 8, and 9 .
that's nine digits all together.
-- The odd ones are 1, 3, 5, 7, and 9 .
There are five odd ones.
-- The even ones are 2, 4, 6, and 8.
There are four of them.
-- Two odd digits are already used, and we can't repeat them.
So we have 7 choices left for the last digit ... 3 odds and 4 evens.
-- Probability = (number of successful choices) / (total possibilities)
Successful choices . . . an odd digit, 3 available
Total possibilities . . . 7 unused digits
Probability = 3/7 (choice C)
Answer:
Taking LHS
=1 by cos theta- cos theta
= (1- cos²0)/ cos0
= sin²0/ cos0 ( because 1-cos²0 is also equals to sin²0)
=RHS hence proved
Answer:
TRUE
Step-by-step explanation:
15>2