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Marianna [84]
3 years ago
6

wilhelmina has 8.3 ounces of peanut butter.if she makes 5 sandwijes with an equal amount ofbpeanut butter on each,how much peanu

t butter does she put on each one?
Mathematics
1 answer:
kotykmax [81]3 years ago
3 0

Peanut butter: 8.3 ounces

Sandwich: 5

Divide 8.3 by 5, for equal amount of peanut butter on each sandwich.

8.3/5 = 1.66

She puts 1.66 ounces of peanut butter on each sandwich.

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Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

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3 years ago
Find the range of the function y= 9x-2, where x&gt;-2
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Step-by-step explanation:hope this helps

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What are the expressions?
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<h2>Explanation:</h2>

Here we need to solve some expressions. Remember the following rules:

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Then, from the left side:

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from the right side:

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Find the Distributive Property <br> 8X46=8X(40+
finlep [7]

Hey There!

8x^46=8x(40+

We move all terms to the left:

8x^46-(8x(40+)=0


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3 years ago
The diffrence between 2 numbers is 1 and their product Is 132
il63 [147K]

Answer:

x = 12

y = 11

For any clarification, Please contact me in the comment section :)

I Hope It Helps .

Step-by-step explanation:

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