The first one is 2x^2+2x-2
the second one is 2x^2-2x-2
the third one is 6h+6k
Answer:
1, 3, 5
Step-by-step explanation:
They're odd, consecutive, and equal 9.
I'm sorry idk how to do it
Answer:
see explanation
Step-by-step explanation:
To determine which ordered pairs are solutions to the equation
Substitute the x and y values into the left side of the equation and if equal to the right side then they are a solution.
(- 1, - 6)
3(- 1) - 4(- 6) = - 3 + 24 = 21 = right side ← thus a solution
(- 3, 3)
3(- 3) - 4(3) = - 9 - 12 = - 21 ≠ 21 ← not a solution
(11, 3)
3(11) - 4(3) = 33 - 12 = 21 = right side ← thus a solution
(7, 0)
3(7) - 4(0) = 21 - 0 = 21 = right side ← thus a solution
The ordered pairs (- 1, - 6), (11, 3), (7, 0) are solutions to the equation
No, the answer is 24th.
The LCM of 3 and 4 is 12.
(3,6,9,12)(4,8,12)
12th April +12=24th April
