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AleksAgata [21]
2 years ago
12

What is the y-intercept of the line that passes through the points (2,-1) and (-3,9)

Mathematics
1 answer:
krek1111 [17]2 years ago
4 0

Answer:

<em>The equation of the straight line y = -2x +3</em>

<em>y-intercept =  3 and m =-2</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the points are ( 2,-1) and (-3,9)

The slope of the line

m = \frac{y_{2}-y_{1}  }{x_{2} -x_{1} } = \frac{9-(-1)}{-3-(2)} = \frac{10}{-5} = -2

<u><em>Step(ii):</em></u>-

The equation of the straight line passing through the point ( 2,-1) and slope m=-2

      y-y₁ = m( x- x₁)

     y -(-1) = -2 ( x-2)

      y +1 = -2x +4

     2x +y +1-4 =0

    2x +y -3 =0

<u><em>Final answer:-</em></u>

<em>The equation of the straight line y = -2x +3</em>

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