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2 years ago

Help please use picture

Mathematics

1 answer:

Katarina [22]2 years ago

4 0

I think it is 22, but I did it in my head so i might be way off

What you do is you “take apart” the net so it has individual rectangles, then you multiply the 2 sides... you do that for each rectangle then add it all up

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What is the vertex of the parabola shown?

Ivenika [448]

10,800 would be the best awnser for you

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3 years ago

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The _____________________________________ Postulate says that If two angles of one triangle are congruent to two angles of anoth

Crank

Answer: Angle sum

Step-by-step explanation:

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2 years ago

Select all of the points that are solutions to the system of linear inequalities that is listed below 10x + 4y < 12 8x -3y &g

liberstina [14]

Answer:

(3, -8) and (2, -10)

Step-by-step explanation:

Given

$10x + 4y < 12$

$8x - 3y > 20$

Required

Select the true coordinate points in (3, -8) (2, 5) (-5, 1) (10, 3) (2, -10)

(3, -8)

x = 3 and y = -8

$10x + 4y < 12$

$10 * 3 + 4 * -8 < 12$

$30 - 32 < 12$

$-2 < 12$ --- True

$8x - 3y > 20$

$8 * 3 - 3 * -8> 20$

$24 +24> 20$

$48> 20$ --- True

(2, 5)

x = 2 and y = 5

$10x + 4y < 12$

$10 * 2 + 4 * 5 < 12$

$20 + 20 < 12$

$40 < 12$ --- False (No need to check the other inequality)

(-5, 1)

x = -5 and y = 1

$10x + 4y < 12$

$10 * -5 + 4 * 1 < 12$

$-46 < 12$ --- True

$8x - 3y > 20$

$8 * -5 - 3 * 1 > 20$

$-43 > 20$ --- False

(10, 3)

x = 10 and y = 3

$10x + 4y < 12$

$10 * 10 + 4 * 3 < 12$

$112 < 12$ --- False (No need to check the other inequality)

(2, -10)

x = 2 and y = -10

$10x + 4y < 12$

$10 * 2 + 4 * -10 < 12$

$-20 < 12$ --- True

$8x - 3y > 20$

$8 * 2 - 3 * -10 > 20$

$46 > 20$ --- True

Hence, the solution to the inequalities are:

(3, -8) and (2, -10)

4 0

2 years ago

On each of five slips of paper, you wrote the words eggs, waffles, pancakes, fruit, and muffin. Every day, you choose one slip f

Luda [366]

The answer is 1/5, or 0.2, because if you're always putting the slip back in, then there will always by 5 slips to choose from, therefore making the probability 1 out of 5. I hope this helps!

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3 years ago

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Evaluate the cosine if the angle of rotation which contains the point (9, -3) on its terminal side

Liono4ka [1.6K]

so we know the terminal point is at (9, -3), now, let's notice that's the IV Quadrant

$\bf (\stackrel{x}{9}~~,~~\stackrel{y}{-3})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{9^2+(-3)^2}\implies c=\sqrt{81+9}\implies c=\sqrt{90} \\\\[-0.35em] ~\dotfill$

$\bf cos(\theta )=\cfrac{\stackrel{adjacent}{9}}{\stackrel{hypotenuse}{\sqrt{90}}}\implies \stackrel{\textit{rationalizing the denominator}}{\cfrac{9}{\sqrt{90}}\cdot \cfrac{\sqrt{90}}{\sqrt{90}}\implies \cfrac{9\sqrt{90}}{90}}\implies \cfrac{\sqrt{90}}{10}\implies \cfrac{3\sqrt{10}}{10}$

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2 years ago