Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
Answer:
Step-by-step explanation:
We know the definition of both functions: 
, and 
A) In order to evaluate what 
, let's first investigate what g(-1) is using the definition for this function:
Now let's find what f(2) is using f(x) definition: 
B) In order to evaluate what 
, let's first investigate what f(3) is using the definition for this function:
Now let's find what g(7) is using the definition for this function:
I can’t rly see the question please make it bigger
Answer:
The Line p
y= 3/4x+ 6.25
Step-by-step explanation:
The points given changed 4 right and 3 up, giving a slope of .75
plug this slope into (1,7) to get the y-intercept. This shows the intercept at 6.25.
Answer:
a) - 11x - 94y / 12 b) x -4 / 5- 3x c) 12x - 11 /10y
Step-by-step explanation:
a) 2x - 6y / 4 - 4y - x/ 12 - 4x - 20y /3
6x - 18y / 12 - 4y - x / 12 - 16x - 80y / 12
= 5x - 14y / 12 - 16x - 80y / 12
- 11x - 94y / 12
b) x /5 - 4/ 3x = x -4 / 5- 3x
c) 2x -3/ 5y - 5- 2x / 10y + x/y
4x - 6 /10y - 5-2x/ 10y + 10x / 10y
2x - 11 / 10 + 10x / 10y
= 12x - 11 /10y
