Please help me to solve the problems

Three friends go bowling the cost per person per game is $ 5.30 the cost to rent shoes is $ 2.50 per person.Their total cost is

siniylev [52]

Find cost of shoes first (7.50)
subtract from the total value (55.20-7.50= 47.7)
then divide by 5.30 (47.7/ 5.3= 9)

4 0

3 years ago

HELP DUE IN 10 MINS!

Scilla [17]

Answer:

$\checkmark \text{B. The area of the circle is } 729\pi,\\\checkmark \text{D. The arc length of the sector is } 12\pi$

Step-by-step explanation:

Area of a circle with radius $r$ : $r^2\pi$

Circumference of a sector with radius $r$ : $2r\pi$

Area of sector with angle $\theta$ : $r^2\pi\cdot \frac{\theta}{360}$ .

Arc length of sector with angle $\theta$ : $2r\pi\cdot \frac{\theta}{360}$

Using these equations, we get the following information:

Area of circle: $27^2\pi=729\pi$

Circumference of a circle: $2\cdot 27\cdot \pi=54\pi$

Area of sector: $27^2\pi\cdot \frac{80}{360}=162\pi$

Arc length of sector: $2\cdot 27\cdot \pi \cdot \frac{80}{360}=12\pi$

3 0

3 years ago

Diagram 7 shows a regular hexagon UVWXYZ.

OLEGan [10]

Answer:

option d is the correct answer

Step-by-step explanation:

use formula for finding sum of all interior angles of regular polygon i.e. (n-2)×180 where n is no of sides of regular polygon then divide it by no. of sides of regular polygon to find measure of one angle of regular polygon and then subtract it from 180° to find the answer

8 0

3 years ago

A high school had 2,300 students in 2010 which increased by 33% in the following four years. How many students are there in 2014

mr Goodwill [35]

Students in 2014 = (100% + 33%) × 2,300
students in 2014 = 133% × 2,300
students in 2014 = 133/100 × 2,300
students in 2014 = 3,059

There are 3,059 students in 2014

4 0

3 years ago

The bases of a trapezoid lie on the lines y=2X +7 and y= 2X -5. Write the equation that contains the midsegment of the trapezoid

ryzh [129]

Given:

The bases of a trapezoid lie on the lines

$y=2x+7$

$y=2x-5$

To find:

The equation that contains the midsegment of the trapezoid.

Solution:

The slope intercept form of a line is

$y=mx+b$

Where, m is slope and b is y-intercept.

On comparing $y=2x+7$ with slope intercept form, we get

$m_1=2,b_1=7$

On comparing $y=2x-5$ with slope intercept form, we get

$m_2=2,b_2=-5$

The slope of parallel lines are equal and midsegment of a trapezoid is parallel to the bases. So, the slope of the bases line and the midsegment line are equal.

$m=m_1=m_2=2$

The y-intercept of one base is 7 and y-intercept of second base is -5. The y-intercept of the midsegment is equal to the average of y-intersects of the bases.

$b=\dfrac{b_1+b_2}{2}$