Ok, if you decrease <span>£2500 by 1% you get 99% remaining
</span>So
99% of £2500 = 0.99 x £2500 = <span>£2475</span>
Answer:
2a(b^3 - 7b + 8)
Step-by-step explanation:
I'm assuming that 2a2b3 is 2a2b^2. If not, this answer isn't correct.
Look at the whole numbers. Is there a number that divides into them evenly? Yes, 2, so you pull 2 from the problem and divide each number by 2. Do the same for each variable.
2a2b3 - 14ab + 16a
2(ab^3 - 7ab +8a)
2a(b^3 - 7b + 8)
Answer:






Step-by-step explanation:
Given

See attachment for proper table
Required
Complete the table
Experimental probability is calculated as:

We use the above formula when the frequency is known.
For result of roll 2, 4 and 6
The frequencies are 13, 29 and 6, respectively
So, we have:



When the frequency is to be calculated, we use:


For result of roll 3 and 5
The probabilities are 0.144 and 0.296, respectively
So, we have:


For roll of 1 where the frequency and the probability are not known, we use:

So:
Frequency(1) added to others must equal 125
This gives:


Collect like terms


The probability is then calculated as:


So, the complete table is:






These three vectors are linearly <u>dependent</u> (details are in the attachment).
Answer:
I get the answer 52°......................