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Sav [38]
3 years ago
12

To test the effectiveness of a business school preparation course, 8 students took a general business test before and after the

course. The results are given below. Exam Score Exam Score Student Before Course (1) After Course (2) 1 530 670 2 690 770 3 910 1,000 4 700 710 5 450 550 6 820 870 7 820 770 8 630 610 If they hope that the prep course is effective in improving the exam scores, what is the alternative hypothesis?
Mathematics
1 answer:
Lisa [10]3 years ago
4 0

Solution :

Group   Before     After

Mean    693.75    743.75

Sd         155.37     143.92

SEM        54.93     50.88

n              8            8

Null hypothesis : The preparation course not effective.

$H_0: \mu_d = 0$

Alternative hypothesis : The preparation course is effective in improving the exam scores.

$H_a : \mu_d>0$  (after -  before)

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The Answer is 72 and number line you should know how to draw, draw like from -20 to 80 or something.

-20 -18 -16     etc. cetera
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3 years ago
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The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

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5 0
3 years ago
Read 2 more answers
A positive integer is 11 more than 18 times another. Their product is 6030. Find the two integers.
allsm [11]

Answer:

18 and 335

Step-by-step explanation:

y = 18x + 11

x * y = 6030

x * (18x + 11) = 6030

18x^2 + 11x = 6030

18x^2 + 11x - 6030 = 0

(18x + 335)(x - 18) = 0

18x + 335 = 0                 x - 18 = 0

18x = -335                      x = 18

x = -335/18

x is gonna have to be a positive number...so x = 18

y = 18x + 11

y = 18(18) + 11

y = 324 + 11

y = 335

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4 0
4 years ago
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A father leaves his money to his four children the first received 1/3 the second received 1/6 and the third received 2/5 how muc
Eduardwww [97]

Answer:

The remaining child got a fraction of  \frac{1}{10}.

Step-by-step explanation:

Lets take the fraction of the money fourth child got is x

Addition of all these fractions should be equal to 1.

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⇒27+30x=30

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⇒x=0.1

Therefore,

The remaining child got a fraction of  \frac{1}{10}.

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steposvetlana [31]
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