A circle doesnt have a sides so 0
Slope of line = tan(120) = -tan(60) = - √3
Distance from origin = 8
Let equation be Ax+By+C=0
then -A/B=-√3, or
B=A/√3.
Equation becomes
Ax+(A/√3)y+C=0
Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/√3)y+C)/sqrt(A^2+(A/√3)^2))
Substitute coordinates of origin (x,y)=(0,0) =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/√(4/3) => C=8*2/√3 = (16/3)√3
Therefore one solution is
x+(1/√3)+(16/3)√3=0
or equivalently
√3 x + y + 16 = 0
Check:
slope = -1/√3 .....ok
distance from origin
= (√3 * 0 + 0 + 16)/(sqrt(√3)^2+1^2)
=16/2
=8 ok.
Similarly C=-16 will satisfy the given conditions.
Answer The required equations are
√3 x + y = ± 16
in standard form.
You can conveniently convert to point-slope form if you wish.
Answer:
-4096
Step-by-step explanation:
8,-16,32,-64,128,-256,512,-1024,2048.-4096
If patio is square it means that area of if is
where a is one side
Now we can substitute A=200 and solve eq
a=
a=14.1421
Now we are rounding to the nearest tenths
a=14.1 because next number is 4 and is less then 5.
The result is 14.1
Answer:
1. -1/2
2. 3/-2
3. 1/2/2
4. 7/2
Step-by-step explanation:
Hope it helped
