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wariber [46]
3 years ago
5

What is 28% as a fraction

Mathematics
2 answers:
Svetach [21]3 years ago
8 0
28% as a fraction is 28/100
marysya [2.9K]3 years ago
3 0
Percent means parts out of 100
28%=28/100=14/50=7/25
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I really am confused on how to write a proof.
kvasek [131]

Since ABCD is a parallelogram, the opposite sides will be parallel and equal,

\begin{gathered} AB=CD \\ BC=AD \end{gathered}

Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,

\begin{gathered} \angle CAD=\angle ACB\text{ (Alternate Interior Angles)} \\ BC=AD\text{ (Opposite sides of parallelogram)} \\ \angle ADB=\angle CBD\text{ (Alternate Interior Angles)} \end{gathered}

So by the ASA criteria, the triangle AED is congruent to the triangle CEB,

Then the corresponding parts of the triangles will be equal,

\begin{gathered} AE=CE \\ BE=DE \end{gathered}

Hence Proved.

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1 year ago
A newspaper writers compensation package includes the total cost of a $150 per month health insurance plan the total cost of a $
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150 x 12 = 1800
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3 years ago
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zubka84 [21]
The answer to your question is the letter G.
8 0
3 years ago
Please help! ASAP! i need help
KonstantinChe [14]

Answer: y= 1 2/3

Step-by-step explanation:

3 0
2 years ago
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A professor has 24 pairs of socks in his drawer. 18 pairs are black and the rest are brown. He always wears black pants. He does
lesya692 [45]

Answer:

The likelihood that the professor's socks matched his pants on both days is 0.5625

Step-by-step explanation:

Total no. of pair of socks = 24

No. of black pairs = 18

We are given that  he selects one pair of socks on Monday and one on Tuesday. Since he has lots of clean socks in the drawer he does not do laundry.

So, It is  a case of replacement

He always wears black pants.

We are supposed to find he likelihood that the professor's socks matched his pants on both days i.e. Black socks both days.

So ,Probability of wearing black socks on Monday = \frac{18}{24}

So ,Probability of wearing black socks on Tuesday =\frac{18}{24}

So,the likelihood that the professor's socks matched his pants on both days = \frac{18}{24} \times \frac{18}{24}=0.5625

Hence the likelihood that the professor's socks matched his pants on both days is 0.5625

4 0
3 years ago
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