All categories

4 years ago

F(x) = 3x – 2 and g(x) = x2 + 1, find (f + g)(x)

Mathematics

1 answer:

Pani-rosa [81]4 years ago

3 0

Option A: x^2 +3x-1 is the correct answer

Step-by-step explanation:

Given functions are:

$f(x) = x-2\\g(x) = x^2+1$

We have to find (f+g)(x), which is the addition of two given functions

So,

$(f+g)(x) = f(x) +g(x)\\= 3x-2 + (x^2+1)\\= 3x-2+x^2+1\\= x^2+3x-2+1\\=x^2+3x-1$

Hence,

Option A: x^2 +3x-1 is the correct answer

Keywords: Functions, addition

Learn more about functions at:

#LearnwithBrainly

You might be interested in

Find the difference

Alisiya [41]

Answer:

the answer is A

Step-by-step explanation:

(9x2 + 10x +4) - (9x2 + 5x -1)

(22+10x) - (17+5x)

5x+5

3 0

4 years ago

Suppose 20% of 300 students choose recycling. How many students choose

GrogVix [38]

Answer:

around 60 kids chose to recycle

Step-by-step explanation:

20% of 300 = 60

8 0

2 years ago

Read 2 more answers

Machine A and machine B both make car parts.

Shalnov [3]

Answer:

Machine A makes 432 on Monday. Machine 2 makes 520 parts on monday. 432+520=952

Step-by-step explanation:

3 0

3 years ago

.It makes sense to measure the number of students in a class in partial quantities.

Tresset [83]

Maybe it’s true? try it

5 0

2 years ago

Which expression is equivalent to the expression below? StartFraction m + 3 Over m squared minus 16 EndFraction divided by Start

Kamila [148]

Option B: $\frac{1}{(m-4)(m-3)}$ is the correct answer.

Explanation:

The given expression is $\frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}$

Simplifying the expression, we have,

$\frac{m+3}{m^{2}-16}\times\frac{m+4}{m^2-9}$

Factor the equations, $m^{2}-16\right$ and $m^{2}-9$ ,we get,

$m^{2}-16\right=m^{2}-4^{2}=(m+4)(m-4)$

$m^{2}-9=m^{2}-3^2=(m+3)(m-3)$

Substituting these factored expressions in the above expression, we have,

$\frac{m+3}{(m+4)(m-4)}\times\frac{m+4}{(m+3)(m-3)}$

Cancelling the common terms $m+3$ and $m+4$ , we get,

$\frac{1}{(m-4)(m-3)}$

Thus, the expression equivalent to $\frac{(\frac{m+3}{m^2-16}) }{(\frac{m^2-9}{m+4} )}$ is $\frac{1}{(m-4)(m-3)}$

Hence, Option B is the correct answer.

3 0

3 years ago

Read 2 more answers