Answer:
2.2 m/s
Step-by-step explanation:
Step one
Given data
An earthquake wave travels through 55 km
hence distance = 55 km
time taken = 25 seconds
<u>Required</u>
<u>the expression relating t and d</u>
Step two:
we know that velocity is
Speed= distance/time
speed= 55/25
Speed= 2.2 m/s
Answer:
9
Step-by-step explanation:
-3^3 +5*(3)^2 +3*-3
-27+5*9+(-9)
-27+45-9
=9
Starting off, we can multiply the third equation by 2 and add it to the third to get rid of both the x and y variables. Next, we get z=1. Plugging that into 3y-5z=-23, we get 3y-5=-23. Adding 5 to both sides, we get 3y=-18. After that, we can divide both sides by 3 to get y=-6. Plugging that into -2x-y-z=-3, we get -2x+6-1=-3=-2x+5. Subtracting 5x from both sides, we get -2x=-8. After that, we can divide both sides by -2 to get x=4.
S (3, 0)
C (5, 1)
W (4, -4)
Explanation
You take the first number and add 6 to it and you get the new number and then you take the second number and subtract 3 from it
S: -3 + 6 = 3
S- 3 - 3 = 0
C: -1 + 6 = 5
C: 4 - 3 = 1
W: -2 + 6 = 4
W: -1 - 3 = -4
<span>The answer should be 14t - 2m2 - 5/2 , if I am correct</span>
