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hichkok12 [17]
4 years ago
15

Evaluate a - b + c, if a = -7, b = 3, c = -2.

Mathematics
2 answers:
Zanzabum4 years ago
8 0

Hello,

Evaluate a - b + c, if a = -7, b = 3, c = -2.

Solution:

a - b + c = (-7) - 3 + (-2)

Remember to follow PEMDAS.

(-7) - 3 + (-2)

= -10 + -2

= -12

Answer:

-12

galben [10]4 years ago
6 0

Answer:

-12

Step-by-step explanation:

(-17)- (3)+ (-2)= answer

go from left to right

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Dafna1 [17]

Answer:

It's 145.5........

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Write as an equation: 1/3 of a shipment of books weights 28 pounds
Crazy boy [7]

Answer:

x=28 (pounds) * 1/3

Step-by-step explanation:

28/3 gives you 1/3 of the shipment weight.

6 0
3 years ago
Solve each radical equation. Be sure to check your solutionsa)√(2x-3)=11b)∛(6-x)=-3
leva [86]

Answer:

a) x = 62

b) x = 33

Step-by-step explanation:

Hi there!

a) Let´s write the equation:

√(2x-3) = 11

Square both sides

2x - 3 = 121

add 3 to both sides of the equation

2x = 124

divide by 2 both sides

x = 62

Let´s check:

√(2x-3) = 11

x = 62

√(2(62)-3) = 11

√(124-3) = 11

√121 = 11

11 = 11

x = 62 satisfies the equation

b) Let´s write the equation:

∛(6 - x) = -3

Cube both sides

6 - x = -27

subtract 6 to both sides

-x = -27 - 6

-x = -33

divide by -1 both sides

x = 33

Now, let´s check the result:

∛(6 - x) = -3

x = 33

∛(6 - 33) = -3

∛(-27) = -3

-3 = -3

x = 33 satisfies the equation

8 0
3 years ago
WRITE THE EQUATION OF THE LINE IN SLOPE INTERCEPT FORM.
nika2105 [10]

Answer:

the first answer ( I think these are 3 different questions) is y = -4x + 7

the second answer is y = -3x + 5

the third answer is y = 6x - 5, because the lines are parallel, they have the same slope and the y int is -5 from the point given.

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=integration%20%5C%3A%20of%20%5Cfrac%7B1%7D%7B2%7D%20%20ln%282x%20%7B%5E%7B2%7D%20%29%20" id="T
In-s [12.5K]

Using properties of the logarithm, you can rearrange the integrand as

\dfrac12\ln(2x^2)=\dfrac{\ln2+\ln x^2}2=\dfrac{\ln2+2\ln x}2=\ln\sqrt2+\ln x

Then recall that the integral of \ln x is

\displaystyle\int\ln x\,\mathrm dx=x(\ln x-1)+C

(or you can find that out by integrating by parts) and so

\displaystyle\int\frac12\ln(2x^2)\,\mathrm dx=(\ln\sqrt2)x+x(\ln x-1)+C

5 0
3 years ago
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