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makkiz [27]
3 years ago
10

SOMEONE PLEASE HELP ME ASAP PLEASE!!!​

Mathematics
1 answer:
viva [34]3 years ago
6 0

Answer:

30°

Step-by-step explanation:

First we take the full amount of degrees from points A to C, which is given as 125° then subtract 94°, which is the given amount from points A to D, this results in 30°

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What is the gcf of 9 and 36
soldier1979 [14.2K]
Factors of 9: 1; 3; 9
Factors of 36: 1; 2; 3; 4; 6; 9; 12; 18; 36

GCF(9; 36) = 9
4 0
3 years ago
McAllister et al. (2012) compared varsity football and hockey players with varsity athletes from noncontact sports to determine
jonny [76]

Answer:

t _{critical} = 1.760

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

H_o: \mu_1 - \mu_2 = 0

Alternative hypothesis;

H_a : \mu_1 - \mu_2 > 0\\

The pooled variance t-Test would have been determined if the population variance are the same.

S_p^2 = \dfrac{(n_1-1)S_1^2+(n_2-1)S^2_2}{(n_1-1)+(n_2-1)}

S_p^2 = \dfrac{(8-1)2.507^2+(8-1)2.8282^2}{(8-1)+(8-1)}

S_p^2 = 7.14

The t-test statistics can be computed as:

t= \dfrac{(x_1-x_2)-(\mu_1 - \mu_2)}{\sqrt{Sp^2 ( \dfrac{1}{n} +\dfrac{1}{n_2})}}

t= \dfrac{(9-6)-0}{\sqrt{7.14 ( \dfrac{1}{8} +\dfrac{1}{8})}}

t= \dfrac{3}{1.336}

t = 2.2450

Degree of freedom df = (n_1 -1) + ( n_2 +1 )

df = (8-1)+(8-1)

df = 7 + 7

df = 14

At df = 14 and ∝ = 0.05;

t _{critical} = 1.760

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.

Conclusion: We reject H_o and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.

To calculate r²

The percentage of the variance is;

r^2 = \dfrac{t^2}{t^2 + df}

r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}

r^2 = \dfrac{5.040025}{5.040025+ 14}

r^2 = 0.2647

7 0
2 years ago
Please help me I don’t have much time please look at the picture
Andre45 [30]

Answer:

Just add the painted miles

2 1/6 + 1 2/3

=3 5/6

then we subtact the total miles that wanna be painted which is 6

6 - 3 5/6

=2 1/6

The answer B

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The 3rd graph should be it
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