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4 years ago

Lines m and n are perpendicular. If the slope of m is zero, then the slope of n is

Mathematics

2 answers:

Fantom [35]4 years ago

7 0

When two lines are perpendicular to each other, then the product of slopes of both lines is equal to “-1”.

Let the slope of line “m” is n1 and slope of line “n” is n2, then ;

n1 x n2 = -1

As per question conditions, n1 = 0;

So n2 = -1/0

Hence n2 = undefined. Thus 2nd option is correct.

Vladimir79 [104]4 years ago

4 0

Answer:

the answer is undefined

Step-by-step explanation:

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hichkok12 [17]

Answer:

corresponding angles

Step-by-step explanation:

<4 and <8 are corresponding angles

Corresponding angles are in matching corners on parallel lines

4 0

4 years ago

Read 2 more answers

What is the equation of the circle shown in the graph? 6 9 12 36

Naddika [18.5K]

You need to add a picture in order for others to understand what you are referring to.

4 0

3 years ago

makvit [3.9K]

Answer:

2 times -4

Step-by-step explanation:

the line jumps backwards 4 times by increments of 2

4 0

3 years ago

Use the point-slope formula to write an equation of the line that passes through (6,23) and has a slope of m= 3. Write the answe

RSB [31]

y=3x+5

plug your coordinate points into the equation for slope (left corner or the paper)

multiply by the denominator on both sides of the equation

x-6 cancels out and leaves y-23=3(x-6)

multiply x and -6 by 3

add 23 to both sides to isolate y

hope this helps!

4 0

3 years ago

Rms/d/e/1FAIpQLSÜDABFGIUJs31xO8JDRug2175ehNYt_F-yaPG7RkyQmW5_puw/viewform?hr_submission=Chki-

geniusboy [140]

Answer:

12709 balls

Step-by-step explanation:

Given

Dimension of Room = 15 ft by 20 ft by 10 ft

Diameter of Ball = 9.2 inches

Required

Determine the number of balls that can be occupied by the room

First, we need to calculate the volume of the room

This is done by multiplying the dimensions of the room

$Volume = 15ft * 20ft * 10ft$

$Volume = 3000ft^3$

Next, we calculate the volume of the ball.

The ball is a sphere.

So:

$Volume = \frac{4}{3}\pi r^3$

Where

$r = \frac{1}{2} * Diameter$

$r = \frac{1}{2} * 9.2$

$r = 4.6\ in$

So:

$Volume = \frac{4}{3}\ * \frac{22}{7} * (4.6in)^3$

$Volume = 407.88419\ in^3$

To calculate the number of balls, we then divide the volume of the room by volume of a ball

$Balls = \frac{3000\ ft^3}{407.88419\ in^3}$

Convert ft^3 to in^3

$Balls = \frac{3000 * 1728in^3}{407.88419\ in^3}$

$Balls = \frac{3000 * 1728}{407.88419}$

$Balls = \frac{5184000}{407.88419}$

$Balls = 12709.4899167$

$Balls = 12709$ -- approximated

Hence, the room will contain 12709 balls

5 0

3 years ago