In this question, you need to use Pythagoras' Theorem, c^2 - b^2 = a^2. In this case, C is 14 and B is 6, so you would do 14^2 - 6^2 = 196 - 36 = 160, and the approximate square root of 160 is 12.6 inches, which is your answer.
I hope this helps!
If 24 marks is 60 %, then full marks is 40
<em><u>Solution:</u></em>
Given that 24 marks is 60 %
We are asked to find the full marks
Let the full marks be "x"
So out of "x" marks, he has got 24 marks
Therefore,
60 % of full marks = 24
60 % of x = 24

Therefore, full marks is 40
<h3><u>Method 2:</u></h3>
If 60 % is 24, then we have to find what is 100 %
60 % = 24
100 % = x
This forms a proportion, So we can solve the sum by cross multiplying

Thus full marks is 40
Answer:
P(A) = 86/100
P(B) = 79/100
P(A') = 14/100
P(A U B) = 95/100
P(A' U B) = 84/100
Step-by-step explanation:
i. P(A) = number of disks with high shock resistance/total number of disks
= (70+16)/100
= 86/100
ii. P(B) = number of disks with high scratch resistance/total number of disks
= (70+9)/100
= 79/100
iii. P(A') = number of disks without high shock resistance/total number of disks
= (100-86)/100
= 14/100
iv. P(AUB) = number of disks with high shock resistance or high scratch resistance/total number of disks
= (70+9+16)/100
= 95/100
v. P(A'UB) = number of disks without high shock resistance or with high scratch resistance/total number of disks
= (5+9+70)/100
= 84/100
2(2x) + 1x = 40 or 4x + 1x = 40 is the result of combining by substitution
<em><u>Solution:</u></em>
Given that we have to combine 2y + 1x = 40 and y = 2x using substitution method
The substitution method for solving systems of equations involves expressing one variable in terms of another, thus removing one variable from an equation.
<em><u>Given equations are:</u></em>
2y + 1x = 40 -------- eqn 1
y = 2x ----------- eqn 2
We can substitute eqn 2 in eqn 1
Which means, substitute y = 2x in place of y in eqn 1
2(2x) + 1x = 40
4x + 1x = 40
5x = 40
x = 8
From eqn 2,
y = 2(8)
y = 16
Thus by combining using substitution method we found the solution