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irakobra [83]
3 years ago
12

40 ➗ [24 - 4 x (2 + 3) ] What is the value of this expression?

Mathematics
2 answers:
STALIN [3.7K]3 years ago
7 0

Answer:

1.7-20x OR 10/6-5x

Step-by-step explanation:

40÷(24-4x(2+3))

first you add the last set of ()

40÷(24-4x(5))

then you multiply by 4x

40÷(24-20x)

since you can't subtract those two you do this

40÷24-20x

divide 40 and 24

you get 1.66666667 then you round up

1.7-20x

<h2>                   OR</h2>

you put 40/24-20x

divide the top and the bottom by 4

(40÷4)/(24÷4) -(20x÷4)

and your answer will be

10/6-5x

Natalija [7]3 years ago
4 0

Answer: this is your answer

  10

_____

6-5x

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Answer:

\large\boxed{(x-2)^2+(y-1)^2=34}

Step-by-step explanation:

The equation of a circle in standard form:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)

Substitute:

h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points (2, 1) and (5, -4):

r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}

Finally we have:

(x-2)^2+(y-1)^2=(\sqrt{34})^2

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