Answer:
There are four major classes of biological macromolecules (carbohydrates, lipids, proteins, and nucleic acids)
Explanation:
There are four major classes of biological macromolecules (carbohydrates, lipids, proteins, and nucleic acids), and each is an important component of the cell and performs a wide array of functions. ... Biological macromolecules are organic, meaning that they contain carbon.
Answer:
207.89g
Explanation:
The formula of the compound is:
Fe₂S₃
Find the molar mass of the compound;
Atomic mass of Fe = 55.845g/mol
S = 32.065g/mol
Now;
Molar mass of Fe₂S₃ = 2 (55.845) + 3 (32.065)
= 207.89g
Answer:
The given statement is false.
Explanation:
Acid as are defined as those substance which gives hydrogen ions in their aqueous solutions.
Base as are defined as those substance which gives hydroxide ions in their aqueous solutions.
The given statement is false.The correct statement is :
Bases increase the concentration of hydroxide ions by donating hydroxide ions to water molecules.
Answer: Provide the nuclear power plant with a plan to properly dispose of and recycle the wastes.
Explanation:
The nuclear power plant is producing huge amounts of electricity which is beneficial to the economy as it pushes growth. Shutting it down or relocating it is therefore not the right solution.
The problem is the radioactive waste being produced so a solution that is specific to this problem should suffice. That solution would be the provision of the nuclear plant with plans to properly dispose of the waste.
Should this happen, the nuclear plant can still stay in the same area and keep contributing to economic growth without adversely affecting people's heath.
The first step is to make a balanced chemical equation.
2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2
Molecular Weights:
CaCl2 = 110.98 g/mol
AgNO3 =170.01
AgCl: 143.45 g/mol
Volume:
CaCl2: 30.0mL=0.03L
AgNO3: 15.0mL=0.015 L
Solving for the limiting reactant one needs to get the mols CaCl2 and mols AgNO3:
CaCl2: 0.150M(mol/L) * 0.03L = 0.0045 moles
AgNO3: 0.100M*0.015L = 0.0015 moles
Since the stoichiometric ratio of AgNO3 to CaCl2 is 2:1
0.0015 mols AgNO3 *(1 mol CaCl2/ 2 mols AgNO3) = 0.00075 mols CaCl2
Since the answer is lesser than CaCl2 then the limiting reactant is AgNO3.
To get the mass of AgCl one will do a stoichiometric calculation with respect to the limiting reactant, AgNO3.
0.0015 moles AgNO3 *