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Ierofanga [76]
3 years ago
15

An atom that has gained or lost electrons is called _____.

Chemistry
2 answers:
jek_recluse [69]3 years ago
7 0
It called cation, Well, When an atom gains or loses an electron, it attains a net charge and becomes an ion. When electrons are lost, the resulting ion is called cation and when electrons are gained, the resulting ion is called an anion. So, Cations have a net positive charge, while anions have a net negative charge. it is true.
tester [92]3 years ago
4 0

Answer:

ions

Explanation:

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5 0
3 years ago
How many oxygen atoms are in the product of this balanced chemical equation
svlad2 [7]

Answer:

two oxygen atoms

There are two oxygen atoms in the reactants and two atoms of oxygen in the product.

Explanation:

8 0
3 years ago
What happens when you grow the same crop over and over again in the same field
irinina [24]
Well there's a couple reasons why. First, the land itself can become “tired" and less fertile<span>. This is because the same type of </span>crop<span> planted repeatedly in the same area keeps draining the land of the same nutrients needed for that plant's growth. Pest can also plant their nest near the crop if the farmer continues to plant the same crop in the same place. 

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6 0
3 years ago
The space race was between
Leviafan [203]

Answer:

the United States and the Soviet Union.

Explanation:

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4 0
2 years ago
2) Calculate the percent composition of each element in Mgso,
iogann1982 [59]

Answer:

2)

\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%

3)

\% Ag=93.1\%\\\\\% O=6.9\%

Explanation:

Hello!

2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:

\% Mg=\frac{24.305}{120.36 } *100\%=20.2\%\\\\\% S=\frac{32.06}{120.36 } *100\%=26.6\%\\\\\% O=\frac{64.00}{120.36 } *100\%=53.2\%

3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:

\% Ag=\frac{215.74}{231.74} *100\%=93.1\%\\\\\% O=\frac{16.00}{231.74} *100\%=6.9\%

Best regards!

7 0
3 years ago
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