To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.
H'(t) = -32t + 64
Now find the critical numbers:
-32t + 64 = 0
-32t = -64
t = 2 seconds
Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):
H'(1) = 32
H'(3) = -32
As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.
To find the height, plug t=2 into H(t):
H(2) = -16(2)^2 +64(2) + 30 = 94
The answer is 94 ft at 2 sec.
X is 63 degrees!
It is equal to the angle marked 63 degrees (angles in that arrangement are always equal)
3x - 7 + 6 = 7x + 6
First shift all the pure numbers to one side
3x = 7x + 6 + 7 - 6
Now add up the pure numbers
3x = 7x + 7
Shift the 7x to the other side
3x - 7x = 7
-4x = 7
Divide 7 by - 4
X = - 1.75
I am not able to see the picture
