Answer:
yidRYoYORoydzyrozoyrsoyraoyeahplhDogdaoyeayeoayorahdlHDLgksOyeayeazhldhdlHkdOyaoyaerhaahdLhKDoywaeya9yaeya9eeY9ey9
Selecting the button assigned
Using the shortcut Keys assigned
Explanation:
By clicking the assigned button one can run a macro and we can assign a short cut key to macro which we created.
So, the two options we can use to run a macro.
Answer:
Hmmm, what would i recommand i think you Should learn skills and become innovative
Explanation:
Sir i'm gonna go toilet and come back
Answer:
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
Explanation:
The Worst case will happen when f(a) > 2*f(b) ; f(b) > 2*f(c) ; f(c) > 2*f(d) ; f(d) > 2*f(e) and f(e) > 2*f(f).
Where f(x) is frequency of character x.
Lets consider the scenario when
f(a) = 0.555, f(b) = 0.25, f(c) = 0.12, f(d) = 0.05, f(e) = 0.02 and f(f) = 0.005
Please see attachment for image showing the steps of construction of Huffman tree:- see attachment
From the Huffman tree created, we can see that endcoding e() of each character are as follows:-
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
e(e) = 11110
e(f) = 11111
So we can see that maximum length of encoding is 5 in this case.
Answer:
29
Explanation:
for n=28:
--------------
Algorithm 1 performs f(n) = n2 + n/2 = 28*28 + 28/2 = 798
Algorithm 2 performs f(n) = 12*28 + 500 = 836
for n=29
--------------
Algorithm 1 performs f(n) = n2 + n/2 = 29*29 + 29/2 = 855.5
Algorithm 2 performs f(n) = 12*29 + 500 = 848
so, for n=29, algorithm 2 will be faster than algorithm 1