Prime factorization involves rewriting numbers as products
The HCF and the LCM of 1848, 132 and 462 are 66 and 1848 respectively
<h3>How to determine the HCF</h3>
The numbers are given as: 1848, 132 and 462
Using prime factorization, the numbers can be rewritten as:
![1848 = 2^3 * 3 * 7 * 11](https://tex.z-dn.net/?f=1848%20%3D%202%5E3%20%2A%203%20%2A%207%20%2A%2011)
![132 = 2^2 * 3 * 11](https://tex.z-dn.net/?f=132%20%3D%20%202%5E2%20%2A%203%20%2A%2011)
![462 = 2 * 3 * 7 * 11](https://tex.z-dn.net/?f=462%20%3D%202%20%2A%203%20%2A%207%20%2A%2011)
The HCF is the product of the highest factors
So, the HCF is:
![HCF = 2 * 3 * 11](https://tex.z-dn.net/?f=HCF%20%3D%202%20%2A%203%20%2A%2011)
![HCF = 66](https://tex.z-dn.net/?f=HCF%20%3D%2066)
<h3>How to determine the LCM</h3>
In (a), we have:
![1848 = 2^3 * 3 * 7 * 11](https://tex.z-dn.net/?f=1848%20%3D%202%5E3%20%2A%203%20%2A%207%20%2A%2011)
![132 = 2^2 * 3 * 11](https://tex.z-dn.net/?f=132%20%3D%20%202%5E2%20%2A%203%20%2A%2011)
![462 = 2 * 3 * 7 * 11](https://tex.z-dn.net/?f=462%20%3D%202%20%2A%203%20%2A%207%20%2A%2011)
So, the LCM is:
![LCM = 2^3 * 3 * 7 * 11](https://tex.z-dn.net/?f=LCM%20%3D%202%5E3%20%2A%203%20%2A%207%20%2A%2011)
![LCM = 1848](https://tex.z-dn.net/?f=LCM%20%20%3D%201848)
Hence, the HCF and the LCM of 1848, 132 and 462 are 66 and 1848 respectively
Read more about prime factorization at:
brainly.com/question/9523814
Step-by-step explanation:
-74+36.2=-37.8
I hope it will help you
Rahul use addition property of equality in step 2.
Solution:
The image of the question is attached below.
Step 1:
![$2 x-\frac{1}{4}-\frac{3}{5} x=\frac{55}{4}](https://tex.z-dn.net/?f=%242%20x-%5Cfrac%7B1%7D%7B4%7D-%5Cfrac%7B3%7D%7B5%7D%20x%3D%5Cfrac%7B55%7D%7B4%7D)
combine like terms together.
![$2 x-\frac{3}{5} x-\frac{1}{4}=\frac{55}{4}](https://tex.z-dn.net/?f=%242%20x-%5Cfrac%7B3%7D%7B5%7D%20x-%5Cfrac%7B1%7D%7B4%7D%3D%5Cfrac%7B55%7D%7B4%7D)
To make the denominator same multiply and divide 2x by 5.
Step 2:
![$\frac{7}{5} x-\frac{1}{4}=\frac{55}{4}](https://tex.z-dn.net/?f=%24%5Cfrac%7B7%7D%7B5%7D%20x-%5Cfrac%7B1%7D%7B4%7D%3D%5Cfrac%7B55%7D%7B4%7D)
By addition property of equality, add
on both side of the equation.
![$\frac{7}{5} x-\frac{1}{4}+\frac{1}{4}=\frac{55}{4}+\frac{1}{4}](https://tex.z-dn.net/?f=%24%5Cfrac%7B7%7D%7B5%7D%20x-%5Cfrac%7B1%7D%7B4%7D%2B%5Cfrac%7B1%7D%7B4%7D%3D%5Cfrac%7B55%7D%7B4%7D%2B%5Cfrac%7B1%7D%7B4%7D)
Step 3:
![$ \frac{7}{5} x=\frac{56}{4}](https://tex.z-dn.net/?f=%24%20%5Cfrac%7B7%7D%7B5%7D%20x%3D%5Cfrac%7B56%7D%7B4%7D)
Step 4:
Multiply by
on both side of the equation.
![x=10](https://tex.z-dn.net/?f=x%3D10)
Hence Rahul use addition property of equality in step 2.
Answer:
$163.85
Step-by-step explanation:
Markup 45% means selling price is 100+45 = 145% of cost
145/100 × 113 = 163.85
yes. 3/6 is also the same thing as 1/2.