Question

Some numbers are formed with closed paths. the digits 0, 4, 6 and 9 each have 1 closed path and 8 has 2. None of the other numbers is formed with a closed path. Given a number determine the total number of closed paths in each of its digits combined.

Answer 1

Answer:

def cal(n):

s=0

while n>0:

r=n%10

if(r==0 or r==4 or r==6 or r==9):

s=s+1

elif r==8:

s=s+2

n=n//10

print(s)

n=int(input("enter number:"))  

print(n)

cal(n)

Explanation:

• Create a function to calculate count of closed path .
• Create a variable to store count of closed path .
• While number is positive , extract last digit of n .
• Reduce number by truncating last digit .
• Make a function call to compute count of path.