Answer:
Endorsement
Explanation:
The term that refers to this is known as an Endorsement. This can be for any product or service and generally involves a celebrity or public figure that in one way or another relates to the product or service being advertised. One example of this would be famous soccer icon Christiano Ronaldo publicly supporting and appearing in Nike advertisements showing off their new soccer cleats.
Answer:
b) Bounded Waiting
Explanation:
int currentThread = 1;
bool thread1Access = true;
bool thread2Access = true;
thread1 { thread2 {
While (true) {
While (true)
{
while(thread2Access == true)
{
while(thread1Access == true)
{
If (currentThread == 2) {
If (currentThread == 1)
{
thread1Access = false; thread2Access = false;
While (currentThread == 2);
While (currentThread == 1);
thread1Access = true; thread2Access = true;
} }
/* start of critical section */ /* start of critical section */
currentThread = 2 currentThread = 1
… ...
/* end of critical section */ /* end of critical section */
thread1Access = false; thread2Access = false;
… ...
} }
} }
} }
It can be seen that in all the instances, both threads are programmed to share same resource at the same time, and hence this is the bounded waiting. For Mutual exclusion, two threads cannot share one resource at one time. They must share simultaneously. Also there should be no deadlock. For Progress each thread should have exclusive access to all the resources. Thus its definitely the not the Progress. And hence its Bounded waiting.
Answer:
def recursive_func():
x = input("Are we there yet?")
if x.casefold() == 'Yes'.casefold():
return
else:
recursive_func()
recursive_func()
Explanation:
We define the required function as recursive_func().
The first line takes user input. The user input is stored in variable x.
The next line compares the user input to a string yes. The function executes the else block if the condition isn't met, that is a recursive call is executed.
IF condition returns the function. The string in variable X is compared to a string 'Yes'. the casefold() is a string function that ignores the upper/lower cases when comparing two strings. (This is important because a string 'yes' is not the same yes a string 'Yes' or 'YES'. Two equal strings means their cases and length should match).
Answer:
1.) Write the formula, which assigns double x to double n raised to the double z power.
Answer: 2\times x → 2\times n^(2\times z<u>)</u>
2.) Write a formula, which will add 5 to the cube of double t times double n, and assign it to double x.
Answer: 5\plus 2\times t^3→2\times x
3.) Write a formula, which will assign double x to square root of the sum of the squares of the lengths of the two legs of a triangle. Declare double leg1, and double leg2, in order to find the hypotenuse. (Pythagorean Theorem)
Answer: 2\times x → \sqrt \{(l^2)_1 + (l^2)_2\}= hypotenuse
4.) Write a program that find the distance between two values on the number line by taking the absolute value of their difference. Assign the answer to double x. The two numbers have been declared as follows:
double num1, num2
Answer: length = \sqrt\{|num2 - num1\|} → 2\times x
Explanation:
