All categories

3 years ago

Can you solve 35÷5+56÷7

Mathematics

2 answers:

VLD [36.1K]3 years ago

8 0

Order of operations

first divide, than add

35/5 = 7
56/7 = 8

7 + 8 = 15

15 is your answer

hope this helps

katrin2010 [14]3 years ago

4 0

Use a calculator.....................

You might be interested in

Evan has a gift card with a balance of $345.09. He used the card to buy a shirt for $17.97.

Jlenok [28]

when he bought the shirt it brought his card balance to $327.12 and then he split the remaining balance with is brother Jack so you would divide $327.12/2 which is $163.56, so they both got $163.56 after he splits

6 0

1 year ago

A jacket at a clothing store is being discounted by 10%. If the jacket was originally priced at x dollars, which of the followin

Bas_tet [7]

Answer:

Step-by-step explanation:

6 0

2 years ago

Jim was thinking of a number. Jim doubles it, then adds 19 to get an answer of 70.1. What was the original number?

Novosadov [1.4K]

Answer:

25.55

Step-by-step explanation:

Let us take the number he thinked of be x .

On doubling it :-

→ N = 2x

On adding 19 :-

→ N = 2x + 19

According to Question :-

→ 2x + 19 = 70.1

→ 2x = 70.1 - 19

→ 2x = 51.1

→ x = 51.1/2

→ x = 25.55

<h3>Hence the required answer is 25.55</h3>

5 0

2 years ago

A) Write down the next two numbers in the following sequence. 45 33 22 12

saveliy_v [14]

Answer: 3 and -5

Step-by-step explanation:

45, 33, 22, 12,

differences =

45-33 = 12

33-22=11

22-12=10

pattern = decreases by one so

12- 9 = 3

3- 8 = -5

5 0

2 years ago

The following question involves a standard deck of 52 playing cards. In such a deck of cards there are four suits of 13 cards ea

olasank [31]

Answer:

(a)No. The probability of drawing a specific second card depends on the identity of the first card.

(b)4/663

(d) 8/663

Step-by-step explanation:

(a)The events are not independent because we are drawing cards without replacement and the probability of drawing a specific second card depends on the identity of the first card.

(b) P(ace on 1st card and jack on 2nd).

$P$(Ace on 1st card) =\dfrac{4}{52}\\ P$(Jack on 2nd card)=\dfrac{4}{51}\\\\$Therefore:\\P(ace on 1st card and jack on 2nd) =\dfrac{4}{52}\times \dfrac{4}{51}\\=\dfrac{4}{663}$

(c)P(jack on 1st card and ace on 2nd)

$P$(Jack on 1st card) =\dfrac{4}{52}\\ P$(Ace on 2nd card)=\dfrac{4}{51}\\\\$Therefore:\\P(jack on 1st card and ace on 2nd) =\dfrac{4}{52}\times \dfrac{4}{51}\\=\dfrac{4}{663}$

(d)Probability of drawing an ace and a jack in either order.

We can either draw an ace first, jack second or jack first, ace second.

Therefore:

P(drawing an ace and a jack in either order) =P(AJ)+(JA)

From parts (b) and (c) above:

$P$(jack on 1st card and ace on 2nd) =\dfrac{4}{663}\\P$(ace on 1st card and jack on 2nd) =\dfrac{4}{663}\\$Therefore:\\P(drawing an ace and a jack in either order)=\dfrac{4}{663}+\dfrac{4}{663}\\=\dfrac{8}{663}$

6 0

3 years ago