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agasfer [191]
3 years ago
8

Graph △ABC with vertices A(4,1),B(−2,3), and C(−1,1) and its image after the glide reflection.

Mathematics
1 answer:
asambeis [7]3 years ago
3 0

I'm in 5th grade

Step-by-step explanation:

I'm in 5th grade

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2x + 2 &gt; 10.<br> A. X&lt;4<br> B. X&gt;4<br> C. X&lt;6<br> D. X&gt;6
OLga [1]
2x + 2 > 10
2x + 2 - 2 > 10 - 2
2x > 8
2x / 2 > 8 / 2
X > 4
8 0
3 years ago
Read 2 more answers
Solve the graphs? Show Your Work?
kari74 [83]

4.\\x\leq10\\\\5.\\x\leq-4\\\\6.\\x\geq4

4 0
3 years ago
H(x)=-x^2+10x-16 Find the 2 x-intercepts
Katena32 [7]

Answer:

x=2   x=8

Step-by-step explanation:

h(x)=-x^2+10x-16

Set this equal to 0

0=-x^2+10x-16

Divide by -1

0/-1=x^2-10x+16

0=x^2-10x+16

Factor

What two numbers multiply to 16 and add to -10

-2*-8 = 16

-2+-8 = -10

0=(x-2) (x-8)

Using the zero product property

x-2=0   x-8=0

x=2   x=8

These are the x intercepts

7 0
4 years ago
WHERE DO THE NUMBERS GO? help!!!!!!
Marat540 [252]

Answer:

Other: \frac{3}{4} , 0.25

Whole Numbers: -20, -6

Natural Numbers: 532, 10, 0, \frac{6}{2}

Step-by-step explanation:

Natural numbers have to be positive whole numbers such as 10 and 0

Whole numbers are similar, but you can have negative numbers here. You just can't put fractions in there.

The 3rd section is a little odd, Integers don't use fractions or decimals, same as whole numbers. The fractions and decimal numbers would go outside of that section.

Extra note: \frac{6}{2} might be a tricky one because it is in fraction form but it is also written as 3. This means it is a natural number. The reason numbers such as \frac{3}{4}  and 0.25 are not natural numbers is because they cannot be put as whole numbers.

6 0
3 years ago
Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the sq
stiv31 [10]

Answer:

18

Step-by-step explanation:

Remark

This is one of those questions that can throw you. The problem is that do you include the original rectangle or not. The way it is written it sounds like you shouldn't

However if you don't the question gives you 2 complex answers. (answers with the sqrt( - 1) in them.

Solution

Let the width = x

Let the length = x + 5

Area of the rectangle: L * w = x * (x + 5)

Area of the smaller squares (there are 2)

Area = 2*s^2

x = s

Area = 2 * x^2

Area of the larger squares = 2 * (x+5)^2

Total Area

x*(x + 5) + 2x^2 + 2(x + 5)^2 = 120                 Expand

x^2 + 5x + 2x^2 + 2(x^2 + 10x + 25) = 120     Remove the brackets

x^2 + 5x + 2x^2 + 2x^2 + 20x + 50 = 120      collect the like terms on the left

5x^2 + 25x +  50 = 120                                   Subtract 120 from both sides.

5x^2 + 25x - 70 = 0                                         Divide through by 5

x^2 + 5x - 14 = 0                                               Factor

(x + 7)(x - 2) = 0                                                 x + 7 has no meaning  

x - 2 =  0

x = 2                                                              

Perimeter

P = 2*w + 2*L

w = 2

L = 2 + 5

L = 7

P = 2*2 + 2 * 7

P = 4 + 14

P = 18

8 0
3 years ago
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