Answer:
C. A graph titled Years Collecting Stamps versus Stamps in Collection has years collecting stamps on the x-axis and stamps in collection on the y-axis. Points are at (2, 100), (3, 100), (3, 125), (4, 150), (4, 175), (5, 175)
Step-by-step explanation:
In the x-axis goes the values from the column 'Number of years collecting stamps' of the table. And In the y-axis goes the values from the column 'Number of stamps in collection' of the table.
To make the graph identify each pair of values in the plane and mark it.
An=a1+d(n-1)
a1=first term
d=common differnce
easy
inptu 4 for n and 10
a4=5+(4-1)1/2
a4=5+3(1/2)
a4=5+3/2
a4=6 and 1/2
4th term is 6 and 1/2
10th term
a10=5+(10-1)1/2
a10=5+(9)1/2
a10=5+9/2
a10=9 and 1/2
4th term is 6 and 1/2
10th term is 9 and 1/2
16+5x =8x-5
Reorder the terms
16+5x = -5+8x
Solving for variable for x
Move all terms containing x to the left, all other terms to the right.
Add -8x to each side of the equation.
16+ -3x = -5 + 8x + -8x
Combine like terms: 5x + -8x=-3x
16+-3x = -5 + 8x + -8x
Combine like terms: 8x + -8x = 0
16+-3x = -5 + 0
16+ -3x = -5
Add -16 to each side of the equation
16+-16 + -3x = -5 + 16
Combine like terms: 16+ -16 = 0
0 + -3x =-5 + -16
-3x = -5 + -16
combine like terms: -5 + -16 = -21
-3x = -21
Divide each side by -3
x=7
The first thing you should do in this case is to know how much paper you need to print for the 17 copies.
We have then:
(17) * (130) = 2210
Then, you must calculate the number of reams you need:
n = (2210) / (500) = 4.42
You need 4 full reams and 42% of a fifth ream. So, the cost will be
C = (4.42) * (3.44) = 15.2048 $
The unit cost of each paper is:
Cu = (15.2048) / (2210) = 0.00688 $
answer
the paper is going to cost 0.00688 $ for those reports
Answer:
A and D have whole grid squares that are the same size and aren't over lapping
C has overlapping grid squares making it hard to count
B can't be used to find area because some of the grid squares are different sizes
You still could use B because four of the smaller squares seems to be equivalent to one of the larger squares
Step-by-step explanation:
