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3 years ago

3ln(2x) + 7 = 15. how do I do this

Mathematics

1 answer:

andrey2020 [161]3 years ago

5 0

Answer:

Step-by-step explanation:

3 ln(2x) + 7 = 15 Subtract 7 from both sides

3 ln(2x) = 15 - 7 Combine

3 ln(2x) = 8 Divide by 3

ln(2x) = 8/3 Do the division. Take the antilog of both sides.

e^ln(2x) = e^(8/3)

2x = 14.392 Divide by 2

x = 14.392

x = 7. 196

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Answer:

$x = \frac{3}{2}orx=-\frac{3}{2}$

Step-by-step explanation:

The given Equation is

$3x^{2} + 2 = 11-x^{2}$ .................(i)

Adding ( $x^{2} -11$ ) on both sides of (i)

$3x^{2}+2+x^{2}-11 = 11-x^{2}+x^{2}-11$

solving and cancelling out the terms will give

⇒ $4x^{2} -9=0$

⇒ $(2x)^{2} -(3)^{2} = 0$ ...................(ii)

Now we Know that

$(a)^{2} -(b)^{2} = (a-b)(a+b)$

Applying this on equation (ii)

$(2x-3)(2x+3)=0$

This will lead us to

Either 2x-3 =0 .......(iii) or 2x+3=0 ..........(iv)

Solving equation (iii) for value of x

2x - 3 =0

adding 3 on both sides

2x -3 +3 = 0+ 3

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Cross multiplying gives

$x=\frac{3}{2}$

Solving equation (iv) for value of x

2x + 3 =0

adding -3 on both sides

2x -3 +3 = 0- 3

2x = -3

Cross multiplying gives

$x=\frac{-3}{2}$

so $x=\frac{3}{2}$ and $x=\frac{-3}{2}$

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A line passes through the point (–2, 7) and has a slope of –5. What is the value of a if the point (a, 2) is also on the line?

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(x1,y1) = (-2,7)
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Forming the equation,
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Putting the values of (x,y) we get,
2 + 5a = -3
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3ln(2x) + 7 = 15. how do I do this​

3ln(2x) + 7 = 15. how do I do this