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Harman [31]
3 years ago
8

There is two part question is on picture correct:brainliest

Mathematics
2 answers:
prohojiy [21]3 years ago
7 0

Answer:

the first one is independent

the second one is dependent

Step-by-step explanation:

Tema [17]3 years ago
5 0

Answer:

The number of dollar bills, <em>d</em>, is the independents variable.

The number of quarters, <em>q</em>, is the depenedent variable.

Step-by-step explanation:

The number of quarters depend on the amont of dollar bills, so the quarters are the depenent variable.  

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Compute the sum:
Nady [450]
You could use perturbation method to calculate this sum. Let's start from:

S_n=\sum\limits_{k=0}^nk!\\\\\\\(1)\qquad\boxed{S_{n+1}=S_n+(n+1)!}

On the other hand, we have:

S_{n+1}=\sum\limits_{k=0}^{n+1}k!=0!+\sum\limits_{k=1}^{n+1}k!=1+\sum\limits_{k=1}^{n+1}k!=1+\sum\limits_{k=0}^{n}(k+1)!=\\\\\\=1+\sum\limits_{k=0}^{n}k!(k+1)=1+\sum\limits_{k=0}^{n}(k\cdot k!+k!)=1+\sum\limits_{k=0}^{n}k\cdot k!+\sum\limits_{k=0}^{n}k!\\\\\\(2)\qquad \boxed{S_{n+1}=1+\sum\limits_{k=0}^{n}k\cdot k!+S_n}

So from (1) and (2) we have:

\begin{cases}S_{n+1}=S_n+(n+1)!\\\\S_{n+1}=1+\sum\limits_{k=0}^{n}k\cdot k!+S_n\end{cases}\\\\\\&#10;S_n+(n+1)!=1+\sum\limits_{k=0}^{n}k\cdot k!+S_n\\\\\\&#10;(\star)\qquad\boxed{\sum\limits_{k=0}^{n}k\cdot k!=(n+1)!-1}

Now, let's try to calculate sum \sum\limits_{k=0}^{n}k\cdot k!, but this time we use perturbation method.

S_n=\sum\limits_{k=0}^nk\cdot k!\\\\\\&#10;\boxed{S_{n+1}=S_n+(n+1)(n+1)!}\\\\\\&#10;

but:

S_{n+1}=\sum\limits_{k=0}^{n+1}k\cdot k!=0\cdot0!+\sum\limits_{k=1}^{n+1}k\cdot k!=0+\sum\limits_{k=0}^{n}(k+1)(k+1)!=\\\\\\=&#10;\sum\limits_{k=0}^{n}(k+1)(k+1)k!=\sum\limits_{k=0}^{n}(k^2+2k+1)k!=\\\\\\=&#10;\sum\limits_{k=0}^{n}\left[(k^2+1)k!+2k\cdot k!\right]=\sum\limits_{k=0}^{n}(k^2+1)k!+\sum\limits_{k=0}^n2k\cdot k!=\\\\\\=\sum\limits_{k=0}^{n}(k^2+1)k!+2\sum\limits_{k=0}^nk\cdot k!=\sum\limits_{k=0}^{n}(k^2+1)k!+2S_n\\\\\\&#10;\boxed{S_{n+1}=\sum\limits_{k=0}^{n}(k^2+1)k!+2S_n}

When we join both equation there will be:

\begin{cases}S_{n+1}=S_n+(n+1)(n+1)!\\\\S_{n+1}=\sum\limits_{k=0}^{n}(k^2+1)k!+2S_n\end{cases}\\\\\\&#10;S_n+(n+1)(n+1)!=\sum\limits_{k=0}^{n}(k^2+1)k!+2S_n\\\\\\\\&#10;\sum\limits_{k=0}^{n}(k^2+1)k!=S_n-2S_n+(n+1)(n+1)!=(n+1)(n+1)!-S_n=\\\\\\=&#10;(n+1)(n+1)!-\sum\limits_{k=0}^nk\cdot k!\stackrel{(\star)}{=}(n+1)(n+1)!-[(n+1)!-1]=\\\\\\=(n+1)(n+1)!-(n+1)!+1=(n+1)!\cdot[n+1-1]+1=\\\\\\=&#10;n(n+1)!+1

So the answer is:

\boxed{\sum\limits_{k=0}^{n}(1+k^2)k!=n(n+1)!+1}

Sorry for my bad english, but i hope it won't be a big problem :)
8 0
3 years ago
Can somebody help me please
Strike441 [17]

Answer:

35m

Explanation:

Perimeter is the sum of all the sides of a shape, or a+b+c=P.

12m+8m+15m = 35m

7 0
3 years ago
Read 2 more answers
Apply the distributive property to factor out the greatest common factor. 35 + 14 =
Galina-37 [17]

Answer: approximately 49

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Solve for x, rounding to the nearest hundredth.<br> 10^3x = 98
Anna71 [15]

Answer:

see explanation

Step-by-step explanation:

10^3x=98

1000x=98

x=98/1000

x=49/500

x=0.98

if it is rounded to the nearest hundredth then x=0

8 0
3 years ago
Someone explain it please
Alina [70]

9514 1404 393

Answer:

  ∠A = 44°

Step-by-step explanation:

In order to find the measure of angle A, you need to know the value of the variable x. This means you need some relation that you can solve to find x.

Happily, that relation is "the sum of angles in a triangle is 180°." This means ...

  84° +(x +59)° +(x +51)° = 180°

  (2x + 194)° = 180° . . . collect terms

  2x = -14 . . . . . . . . . . divide by °, and subtract 194

  x = -7 . . . . . . . . . . . .divide by 2

Now, the measure of angle A is ...

  ∠A = (x +51)° = (-7 +51)°

  ∠A = 44°

4 0
3 years ago
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