3.9 x 10³g
Explanation:
Given parameters;
concentration = 48g/m³
Room dimension = 12 x 12.5 x 18.5ft
unknown:
Mass of carbon dioxide in the room = ?
Solution:
We know that in a room the concentration of carbon monoxide is 48g/m³
To find the mass of the carbon monoxide in a given room, we simply multiply the given concentration level with the volume of the room.
Mass of carbon monoxide = concentration x volume of room
To find the volume of room;
Dimension = 12 x 12.5 x 18.5 in ft to m;
1ft = 0.31m
12ft to meter is 0.31 x 12 = 3.72m
12.5ft to meter is 0.31 x 12.5 = 3.88m
18.5ft to meter is 0.31 x 18.5 = 5.74m
Volume of the room = 3.72 x 3.88 x 5.74 = 82.8m³
Mass of carbon monoxide = concentration x volume of room
Mass of carbon monoxide = 48 x 82.8 = 3.9 x 10³g
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