Answer:
True
Explanation:
if not you can't support it
This is a D. combustion reaction
That is because you add O2 which is necessary for a combustion, while the results are CO2 and water. What you are missing is a ---> after the 2O2 (g)
Answer:
pH = 12.8
Explanation:
HF + NaOH → F⁻ + Na⁺ + H₂O
<em>1 mole of HF reacts with 1 mole of NaOH</em>
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Initial moles of HF and NaOH are:
HF = 0.018L × (0.308mol / L) = 5.544x10⁻³mol HF
NaOH = 0.023L × (0.361mol / L) = 8.303x10⁻³mol NaOH
That means moles of NaOH remains after reaction are:
8.303x10⁻³mol - 5.544x10⁻³mol = <em>2.759x10⁻³moles NaOH</em>
Total volume is 18.0mL + 23.0mL = 41.0mL = 0.0410L
Molar concentration of NaOH is
2.759x10⁻³moles NaOH / 0.0410L = 0.0673M = [OH⁻]
pOH = - log [OH⁻] = 1.17
As pH = 14 - pOH
<em>pH = 12.8</em>
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Answer:
maintain
Explanation:
i don't know it's a guess
Answer:
D) 1.6 x 10⁻¹⁴
Explanation:
The solubility-product equilibrium constant for Ag₂SO₃ is given by the expression
Ksp = [Ag⁺]² [SO₃²⁻]
where [Ag⁺] and [SO₃²⁻] are the concentration of the species dissolved in solution for the equlibrium
Ag₂SO₃ (s) ⇄ 2 Ag⁺ + SO₃²⁻
we are given the concentration of Ag⁺ and from the stoichiometry of the equilibrium, the concentration of SO₃²⁻ is half that value, so
[Ag⁺]² = 3.2 x 10⁻⁵ M
[SO₃²⁻] = 3.2 x 10⁻⁵ M / 2 = 1.6 x 10⁻⁵ M
plugging these values into the solubility product constant equation we have
Ksp = (3.2 x 10⁻⁵)² x (1.6 x 10⁻⁵) = 1.6 x 10¹⁴
Therefore D is the correct answer.