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fgiga [73]
3 years ago
7

If an acid or alkali is diluted by a factor of 10, what effect will this have on its pH?

Chemistry
1 answer:
Alisiya [41]3 years ago
5 0

Answer: When an acidic solution is diluted with water the concentration of H + ions decreases and the pH of the solution increases towards 7.

Explanation:

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What volume of 0.160 m li2s solution is required to completely react with 130 ml of 0.160 m co no3 2?
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The  volume  of  0.160    m   Li2S  solution  required  to  completely  react  with  130 ml  of 0.160  CO(NO3)2  is calculated   as  below

write the  reacting  equation

Co(NO3)2 +  Li2S = 2LiNO3  +  COS

find the    moles  of CO(NO3)2  = molarity  x  volume

=  130 ml  x  0.160=20.8  moles

since the reacting moles between CO(NO3)2  to LiS  is   1:1  the  moles of LiS  is  also  20.8  moles

volume  of Lis  is  therefore =  moles of Lis/ molarity  of LiS

=  20.8/0.160 =  130 Ml
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3 years ago
N__________ is the study of atoms.
AlekseyPX
I think the answer might be nuclear physics
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I NEED HELP PLEASE, THANKS! :)
marin [14]

Answer:

\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}

Explanation:

1. Calculate the moles of copper(II) hydroxide

\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}

2. Calculate the molecules of copper(II) hydroxide

\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}

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3 years ago
A small sack of sand has a density of 1.5 g/cm3 and a mass of 1500 g. How much space (volume) does the sand occupy?
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The answer would be 1000 cm3
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What is the main difference between the Eubacteria and Archaebacteria kingdoms and the protista, fungi, plantae and Animalia kin
gregori [183]

The main difference between the Eubacteria and Archaebacteria kingdoms and the protista, fungi, plantae, and animal kingdoms is that Eubacteria and Archaebacteria are prokaryotes, while protista, fungi, plantae, and animal kingdoms are eukaryotes.

<h3>What is the Six Kingdoms Classification?</h3>

In the six kingdoms of classification, there are Eubacteria, Archaebacteria, Protista, Fungi, Plantae, and Animalia. The Eubacteria is a prokaryote, and its cell membrane is made up of peptidoglycan, teichoic acid, etc. Archaea are also prokaryotes, but their cell membrane composition differs from that of bacteria, so they are classified separately.

The eukaryotes are further classified into protista, fungi, plantae, and animalia depending upon their feeding patterns, complexity, etc. Protists may be unicellular or multicellular. Plants are autotrophs, fungi and animals are heterotrophs.

Eubacteria and Archaebacteria are examples of prokaryotes, whereas protists, fungi, plantae, and animals are examples of eukaryotes.

Learn more about the Six Kingdoms Classification, here

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