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Igoryamba
2 years ago
12

A student writes the following explanation of how one type of compound is formed. these compounds are made by the repeated joini

ng of one smaller unit to the end of a growing chain. the units are generally alkenes, which retain all their atoms in the chain. a compound which undergoes a similar process is polyethylene. which process is being described? condensation polymerization addition polymerization dehydrohalogenation dehydrogenation
Chemistry
2 answers:
tatyana61 [14]2 years ago
6 0

In the given question according to the information the process of polymerization is an addition polymerization.

<h3>What is polymerization?</h3>

Polymerization is a process in which addition of many small molecules takes place for the formation of a large three dimensional substance known as polymer.

In the polymerization of polyethene the small repeating molecule is ethene and in this process product formed due to the addition process to the double bond of the ethene.

  • In condensation polymerisation removal of water molecule or any other molecule takes place.
  • In dehydrogenation polymerisation removal of hydrogen molecule takes place.
  • In dehydrohalogenation polymerisation removal of hydrogen halide molecule takes place.

Hence given process is an addition polymerisation.

To know more about polymerisation, visit the below link:

brainly.com/question/17932602

vfiekz [6]2 years ago
5 0

Answer:

<em>To Put It Simply The Correct Answer is B.) Addition Polymerization</em>

Explanation:

Edge 2022

Got A 90% On The Quiz And This Was One Of My Right Answers

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by radiation from the Earth's surface

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What are the empirical and molecular formulas of a hydrocarbon if combustion of 2.10 g of the compound yields 6.59 g co2 and 2.7
mariarad [96]

 The  empirical  formula    of hydrocarbon is  CH2

The  molecular formula  of the  hydrocarbon is  C6H12


    <u><em>Explanation</em></u>

Hydrocarbon  is  made up  of carbon and hydrogen


<h3><u><em> </em></u>Empirical formula  calculation</h3>

 Step 1:  find  the  moles   CO2  and  H2O

moles =mass/molar mass

moles   of CO2 =  6.59 g/ 44 g/mol = 0.15 moles

moles of H2O = 2.70 g / 18 g/mol =  0.15  moles

Step 2: Find the moles  ratio  of Co2:H2O  by diving  each mole by smallest mole(0.15)

that  is  for  CO2 = 0.15/0.15  =1

              For H2O = 0.15/0.15 =1

therefore  the mole ratio  of Co2 : H2O = 1:1  which  implies that 1 mole of Co2  and 1  mole of H2O is  formed  during combustion reaction.


From the  the law of mass conservation the number  of atoms in reactant side  must  be equal to  number of  atoms  in product side

therefore  since  there 1 atom  of C  in product side there  must be 1 atom of C  in reactant  side.

In addition  there is 2 H atom in product  side  which should be the  same  in reactant side.  

From information above the empirical formula is therefore = CH2


Molecular formula  calculation

[CH2}n= 84 g/mol

[12+ (1x2)] n = 84 g/mol

14 n =  84 g/mol

n = 6

multiply the  each subscript  in CH2  by  6

 Therefore the molecular formula = C6H12




5 0
3 years ago
When elemental boron, B, is burned in oxygen gas, the product is diboron trioxide. If the diboron trioxide is then reacted with
zalisa [80]

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.  

The chemical equation for the reaction of elemental boron and oxygen gas follows:

4B+3O_2\rightarrow 2B_2O_3

By Stoichiometry of the reaction:

4 moles of elemental boron reacts with 3 moles of oxygen gas to produce 2 moles of diboron trioxide.

The chemical equation for the reaction of diboron trioxide and water follows:

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Hence, the chemical equations are written above.

3 0
3 years ago
A silver cube with an edge length of 2.42 cm and a gold cube with an edge length of 2.75 cm are both heated to 85.4 ∘C and place
kakasveta [241]

Answer:

Explanation:

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mass of silver cube = volume x density

= 14.17 x 10.49 = 148.64 gm

Volume of gold cube = 2.75³ = 20.8  cm³

mass of gold cube =  20.8 x 19.3 = 401.44 gm

specific heat of silver and gold are .24 and .129 J /g°C

mass of 112 mL water = 112 g

Heat absorbed = heat lost = mass x specific heat x temperature fall or rise

Heat lost by metals

= 148.64 x .24 x ( 85.4 -T) + 401.44 x .129 x ( 85.4 - T )

= (35.67 + 51.78 ) x ( 85.4 - T )

87.45 x ( 85.4 - T )

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Heat gained by water

= 112 x 1 x ( T - 20.5 )

= 112 T - 2296

Heat lost = heat gained

7468.23 - 87.45 T = 112 T - 2296

199.45 T = 9764.23

T = 48.95° C

7 0
3 years ago
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