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4 years ago

Will a liquid turn into a gas if the pressure of the liquid is increased and no thermal energy is added to the liquid

1 answer:

7 0

No,a liquid will not turn into a gas if the pressure of the liquid is increased and no thermal energy is added to the liquid.

Answer: No

<u>Explanation:</u>

There are three type of substances solid,liquid and gas.State of matter of various substances can be easily changed.If we talk about liquid it will turn into gas if we decrease the pressure on liquid. But on the other hand if pressure is increased it will turn into solid.

Thermal energy is the energy that comes from heating the liquid.If temperature is increased then particles of liquid will move rapidly and it will turn into gas.But if temperature reduces than particles will move slowly and liquid will freeze.

So liquid will not change into gas only by increasing the pressure without the addition of thermal energy.Rather liquid will turn into solid if pressure is increased and thermal energy is not present.

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As steam is slowly injected into a turbine, the angular acceleration of the rotor is observed to increase linearly with the time

gavmur [86]

Answer:

217.04 rad/s

Explanation:

We are given that

Initial velocity, $\omega_0=0$

t=10 s

Number of rev=20

We have to find the angular velocity at t=24 s

$\theta_1=2\pi\times 20=40\pi rad$

$\alpha=kt$

$\frac{d\omega}{dt}=kt$

$\int d\omega=\int_{0}^{t} ktdt$

$\omega=\frac{kt^2}{2}$

$\frac{d\theta}{dt}=\frac{kt^2}{2}$

$\int d\theta=\int_{0}^{t}\frac{kt^2}{2} dt$

$\theta=\frac{kt^3}{6}$

Substitute the values

$40\pi=\frac{k(10)^3}{6}$

$k=\frac{40\pi\times 6}{(10)^3}=\frac{24\pi}{100}$

Substitute the value of k and t=24

$\omega=\frac{24\pi\times (24)^2}{2\times 100}=217.04 rad/s$

8 0

4 years ago

What might say the first stage of photosynthesis powers the energy engine of the living world what do you think this sentence me

zzz [600]

I am having trouble on the same question.

8 0

3 years ago

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An athlete can exercise by making mechanical waves in ropes. What is the

saveliy_v [14]

Answer:

Explanation:

3 0

3 years ago

A stiff wire 44.0 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l

Helga [31]

The magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

Explanation:

It is known that the force acting on a current carrying conductor placed in a magnetic field is

$F=BIL sin theta$

Here B is the magnetic field, I is the current flowing through the wire and L is the length of the wire which is given as 44 cm.

Since the wire is bended in the middle at right angle so the length of the two sides of the wire will be 22 cm each. Also one part is lying over z axis and another part lies in the plane of xy in the equation of line y = 2x. So the slope of this wire will be

$\frac{y}{x} =2$

This will be equal to tan θ.

So θ = tan⁻¹ (2) =63.4°

Then, the length of the wire will be written as components of i, j and k.

$L = (-22)k+(22) cos ( 63.4) i+(22) sin (63.4)j$

$L = 0.098 i+0.197 j-0.22k$

Then,

F = I (L × B)

$F = 20.5 ((0.0985 i + 0.197 j -0.22k) * (0.316 i))$

$F = 20.5 (\left[\begin{array}{ccc}i&j&k\\0.098&0.197&-0.22\\0.316&0&0\end{array}\right] )$

$F = 20.5(i(0)-j(0-(-0.22*0.316))+k(0-(0.316*0.197))) = 20.5(-0.069 j-0.062 k)$

$F = -1.415 j-1.271 k$

The magnitude of force on the wire will be

$F = \sqrt{(-1.415)^{2}+(-1.27)^{2} } = \sqrt{3.615}=1.90 N$

And the direction can be found by the tan inverse of the ratio of k component to j component of the force.

$theta = tan-1(\frac{-1.271}{-1.415})= 41.9 degrees$

So the magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

5 0

4 years ago

Consider a heat engine that inputs 10 kJ of heat and outputs 5 kJ of work. What are the signs on the total heat transfer and tot

Oksi-84 [34.3K]

Answer:

Total heat transfer is positive

Total work transfer is positive

Explanation:

The first law of thermodynamics states that when a system interacts with its surrounding, the amount of energy gained by the system must be equal to the amount of energy lost by the surrounding. In a closed system, exchange of energy with the surrounding can be done through heat and work transfer.

Heat transfer to a system is positive and that transferred from the system is negative.

Also, work done by a system is positive while the work done on the system is negative.

Therefore, from the question, since the heat engine inputs 10kJ of heat, then heat is being transferred to the system. Hence, the sign of the total heat transfer is positive (+ve)

Also, since the heat engine outputs 5kJ of work, it implies that work is being done by the system. Hence the sign of the total work transfer is also positive (+ve).

5 0

3 years ago