All categories

4 years ago

The word back is up there!!!

Physics

1 answer:

Vera_Pavlovna [14]4 years ago

5 0

Mech waves: travel is faster as density of matter increases
EM waves: can pass through matter, travel is slowed as density of matter increases
I think that's all, tell me if I missed anything.

You might be interested in

Which of these organs is an endocrine structure?

Gre4nikov [31]

Answer: Actually three of them are. The ovaries, the uterus and fallopian tubes.

6 0

2 years ago

Mumz [18]

Answer

Procedural bias occurs when the unfair amount of pressure is applied to complete their response quickly.

Measurement bias occurs when there is systematic or random error occur while taking the reading.

Design bias occur when the research fails to encounter all the aspects of the projects before presenting conclusion.

1) The correct answer is option B.

Balance is miscalibrated hence there will be systematic error which is a type of measurement bias.

2) The correct answer is option A.

Limiting response time for participant is an example of Procedural bias.

3) The correct answer is option A

Here, Jackie has not surveyed the diverse group so it is the case of design bias

8 0

4 years ago

Can you please answers these for me please today is the last day to turn in work and I need this to pass please I’m begging than

Ymorist [56]

Answer:

1. F = ma F = 0.2kg * 20m/s² = 4Kg * m/s² = 4N

2. F = ma F - 18Kg * 3m/s² = 54Kg * m/s² = 54N

3. F = ma F = 0.025Kg * 5m/s² = 0.125N

4. F = ma F = 50Kg * 4m/s² = 200N

5. F = ma F = 70Kg * 4m/s² = 280N

6. F = ma F = 9Kg * 9.8m/s² = 88.2N

Explanation:

Hope this helps ! ^^

8 0

2 years ago

How many significant figures does the value 0.080 have? 1 2 3 4

lara [203]

2. The zeros in front do not matter

3 0

4 years ago

A 51.0 kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 10.0 m th

shepuryov [24]

Answer:

The final speed of the crate is 12.07 m/s.

Explanation:

For the first 10.0 meters, the only force acting on the crate is 225 N, so we can calculate the acceleration as follows:

$F = ma$

$a = \frac{F}{m} = \frac{225 N}{51.0 kg} = 4.41 m/s^{2}$

Now, we can calculate the final speed of the crate at the end of 10.0 m:

$v_{f}^{2} = v_{0}^{2} + 2ad_{1}$

$v_{f} = \sqrt{0 + 2*4.41 m/s^{2}*10.0 m} = 9.39 m/s$

For the next 10.5 meters we have frictional force:

$F - F_{\mu} = ma$

$F - \mu mg = ma$

So, the acceleration is:

$a = \frac{F - \mu mg}{m} = \frac{225 N - 0.17*51.0 kg*9.81 m/s^{2}}{51.0 kg} = 2.74 m/s^{2}$

The final speed of the crate at the end of 10.0 m will be the initial speed of the following 10.5 meters, so:

$v_{f}^{2} = v_{0}^{2} + 2ad_{2}$

$v_{f} = \sqrt{(9.39 m/s)^{2} + 2*2.74 m/s^{2}*10.5 m} = 12.07 m/s$

Therefore, the final speed of the crate after being pulled these 20.5 meters is 12.07 m/s.

I hope it helps you!

7 0

3 years ago