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Studentka2010 [4]
3 years ago
10

Clare ran 4 miles on Monday. Then for the next six days, she ran the same distance each day. She ran a total of 22 miles during

the week. How many miles did she run on each of the 6 days?
Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
8 0

Answer:

3

Step-by-step explanation:

22

-4, ÷6

Semenov [28]3 years ago
4 0

Answer:

3 miles

Step-by-step explanation:

4+6x=22

6x=18

x=3

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How do I factor 16x^2 and -49y^2??
jeyben [28]
(4x-7y)(4x+7y)

4x times 4x= 16x^2
-7y times 7y= -49y^2
8 0
3 years ago
The area of a circle is 616cm find the radius​
Leokris [45]
<h3>Given :-</h3>

  • Area of Circle = 616 cm²

<h3>To Find :-</h3>

  • Radius of a circle = ?

<h3>Solution :-</h3>

☼︎ <u>Radius of the Circle</u>;

<h3>Using Formula:</h3>

\\ \red\bigstar {\underline{\boxed{\color{springgreen}{\textsf{ \textbf{ \: Area \: of \: circle= \:  \: π \:  r \: ² \: }}}}}} \\\\

<u>Putting values in the formula;</u>

\\  \sf \implies \: Area \:  =  \: \pi \: r \:  ^{2}  \\

\\  \sf \implies \: 616 \:  =  \:\frac{22}{7}  \times  \: r \:  ^{2}  \\

\\  \sf \implies \: 616 \: \times  \: \frac{7}{22}  \:  =  \: \: r \:  ^{2}  \\

\\  \sf \implies \:  \: \frac{ \:  \: 4312 \:  \: }{22}  \:  =  \: \: r \:  ^{2}  \\

\\  \sf \implies \:  \:  \cancel{\frac{ \:  \: 4312 \:  \: }{22}  }\:  =  \: \: r \:  ^{2}  \\

\\  \sf \implies \:  \:   \: 196 \:  \: =  \: \: r \:  ^{2}  \\

\\  \sf \implies \:  \:r \:  ^{2}  =    \: 196 \:  \:   \: \:  \\

\\  \sf \implies \:  \:r \:   =    \sqrt{ \: 196 \:  } \\

\\  \bf \implies \:  \:Radius  \:   =    14 \: cm \\

henceforth, the Radius of a circle is 14 cm ...!!

6 0
1 year ago
Read 2 more answers
(K3+2k2-82k-28)/(k+10)
Ne4ueva [31]

So for this, we will be using synthetic division. To set it up, have the equation so that the divisor is -10 (since that is the solution of k + 10 = 0) and the dividend are the coefficients. Our equation will look as such:

<em>(Note that synthetic division can only be used when the divisor is a 1st degree binomial)</em>

  • -10 | 1 + 2 - 82 - 28
  • ---------------------------

Now firstly, drop the 1:

  • -10 | 1 + 2 - 82 - 28
  •       ↓
  • -------------------------
  •        1

Next, you are going to multiply -10 and 1, and then combine the product with 2.

  • -10 | 1 + 2 - 82 - 28
  •       ↓ - 10
  • -------------------------
  •        1 - 8

Next, multiply -10 and -8, then combine the product with -82:

  • -10 | 1 + 2 - 82 - 28
  •       ↓ -10 + 80
  • -------------------------
  •        1 - 8 - 2

Next, multiply -10 and -2, then combine the product with -28:

  • -10 | 1 + 2 - 82 - 28
  •       ↓ -10 + 80 + 20
  • -------------------------
  •        1 - 8 - 2 - 8

Now, since we know that the degree of the dividend is 3, this means that the degree of the quotient is 2. Using this, the first 3 terms are k^2, k, and the constant, or in this case k² - 8k - 2. Now what about the last coefficient -8? Well this is our remainder, and will be written as -8/(k + 10).

<u>Putting it together, the quotient is k^2-8k-2-\frac{8}{k+10}</u>

8 0
2 years ago
Can anyone figure this out?
Verizon [17]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

5 0
3 years ago
Find the following for the given f(x) and g(x) F(x)=2x+3;g(x)=3x+1
zheka24 [161]

Answer:

this is questions in class 10ICSE mathematics chapter linear equations

8 0
3 years ago
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