Suppose that Aces can be either high or low; that is, that {A, 2, 3, 4, 5} is a straight, and so is {10, Jack, Queen, King, Ace}
Mumz [18]
Answer:
If OR is exclusive in the question, meaning that Ace can either be high or low but not both would give you 36 possible combinations. However the question isn't exactly stated in a way that makes it easy to interpret this. Your logic is right though, and it could be an error on your sources part. The possible combos are
A 2 3 4 5
2 3 4 5 6
3 4 5 6 7
4 5 6 7 8
5 6 7 8 9
6 7 8 9 10
7 8 9 10 J
8 9 10 J Q
9 10 J Q K
10 J Q K A
How I understand from your writing next term is equal previous plus 3,
if 1st is -4, then next (second) should be -4+3= -1
Given, a = 1
common difference = 3
Eighth term = a+(n-1)d = 1+(8-1)3
= 1 + 21 = 22
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>
Answer:
The answer is 6,992 :)
Step-by-step explanation:
