Answer:

Step-by-step explanation:
Given,
Red marbles = 3,
Green marbles = 10,
So, the total marbles = 3 + 10 = 13,

Since, here replacement is not allowed,
Thus, the probability of getting a green marble and a red marble
= first red and second green + first green second red




Note : The probability of getting a green marble first and a red marble second
= 


Note: Actually, the division problem should be in reverse order. It should be given as
---------(i)
But according to the given problem (x + 1) / (x² + 3 x + 2).
Here, (x² + 3 x + 2) > (x + 1)
or, (x + 2) > 1
Concept: By using the property of division, if the numerator is less than the denominator then the quotient will always be 0 (zero)
Therefore the option (d) 0 will be the correct option.
Answer:
The desired equation is y = (-8/3)x + 26/3.
Step-by-step explanation:
Moving from (1,6) to (4, -2) involves an increase of 3 in x and a decrease of 8 in y. Thus, the slope of the line thru these two points is m = rise / run = -8/3.
Using the slope-intercept form of the eq'n of a straight line and inserting the data given (slope = m = -8/3, x = 4, y = -2), we get:
y = mx + b => -2 = (-8/3)(4) + b, or -2 = -32/3 + b
Multiply all terms by 3 to clear out the fraction:
-6 = -32 + 3b.
Then 26 = 3b, and b = 26/3.
The desired equation is y = (-8/3)x + 26/3.