Could you help me find the volume?

Mathematics

2 answers:

mestny [16]3 years ago

8 0

Volume of what? volume of cube etc

Mekhanik [1.2K]3 years ago

6 0

Hello,
V of the right triangular prism=B×h
or
V=1/2l×w×h
For this problem, I would prefer the second formula
V=1/2×5×11×6
V=30×1/2×11
V=165 cubic feet. As a result, A is the final answer!

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Help me please I forgot my notes at school

sukhopar [10]

1/2 x 6 = 3
3 x 8 = 24
24/6 = 4
4 - 1 = 3

3 is your answer

hope this helps

6 0

3 years ago

Read 2 more answers

1. Two object accumulated a charge of

In-s [12.5K]

Answer:

The magnitude of the electric force between these two objects

will be: 181.274 N.

i.e. F $=181.274$ N

Step-by-step explanation:

Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8 μC = 2.8 × 10⁻⁶ C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

$F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}$

$=\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $\mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4$