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3 years ago

Could you help me find the volume?

Mathematics

2 answers:

mestny [16]3 years ago

8 0

Volume of what? volume of cube etc

Mekhanik [1.2K]3 years ago

6 0

Hello,
V of the right triangular prism=B×h
or
V=1/2l×w×h
For this problem, I would prefer the second formula
V=1/2×5×11×6
V=30×1/2×11
V=165 cubic feet. As a result, A is the final answer!

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Steve's mom's age is 7 years less than 3 times Steve's ages.

murzikaleks [220]

Answer:

y = 3x + 7

(Not sure what the question was so, I just put it in slope intercept form)

Step-by-step explanation:

Let x be Steve's age.

Steve = x

Steve's Mom = y

Now let's create an equation:

y - 7 = 3x

y = 3x + 7

(Not sure what the question was so, I just put it in slope intercept form)

Please let me know if I misunderstood the question that way I can help you! <3

3 0

3 years ago

Read 2 more answers

Integration questions .

dlinn [17]

$\\\\\ \textbf{a)}\\\\~~~\displaystyle \int (6x- \sin 3x) ~ dx\\\\=6\displaystyle \int x ~ dx - \displaystyle \int \sin 3x ~ dx\\\\=6 \cdot \dfrac{x^2}2 - \dfrac 13 (- \cos 3x) +C~~~~~~~~~~~;\left[\displaystyle \int x^n~ dx = \dfrac{x^{n+1}}{n+1}+C,~~~n \neq -1\right]\\\\ =3x^2 +\dfrac{\cos 3x}3 +C~~~~~~~~~~~~~~~~~~~~;\left[\displaystyle \int \sin (mx) ~dx = -\dfrac 1m ~ (\cos mx)+C \right]\\$

$\textbf{b)}\\\\~~~~\displaystyle \int(3e^{-2x} +\cos (0.5 x)) dx\\\\=3\displaystyle \int e^{-2x} ~dx+ \displaystyle \int \cos(0.5 x) ~dx\\\\\\=-\dfrac 32 e^{-2x} + \dfrac 1{0.5} \sin (0.5 x) +C~~~~~~~~~~~~~~;\left[\displaystyle \int e^{mx}~dx = \dfrac 1m e^{mx} +C \right]\\\\\\=-\dfrac 32 e^{-2x} + 2 \sin(0.5 x) +C~~~~~~~~~~~~~~~~~;\left[\displaystyle \int \cos(mx)~ dx = \dfrac 1m \sin(mx) +C\right]\\\\\\=-1.5e^{-2x} +2\sin(0.5x) +C$

$\textbf{a)}\\\\y = \displaystyle \int \cos(x+5) ~ dx\\\\\text{Let,}\\\\~~~~~~~u = x+5\\\\\implies \dfrac{du}{dx} = 1+0~~~~~~;[\text{Differentiate both sides.}]\\\\\implies \dfrac{du}{dx} = 1\\\\\implies du = dx\\\\\text{Now,}\\\\y= \displaystyle \int \cos u ~ du\\\\~~~= \sin u +C\\\\~~~=\sin(x+5) + C$

$\textbf{b)}\\\\y = \displaystyle \int 2(5x-3)^4 dx\\\\\text{Let,}\\~~~~~~~~u = 5x-3\\\\\implies \dfrac{du}{dx} = 5~~~~~~~~~~;[\text{Differentiate both sides}]\\\\\implies dx = \dfrac{du}5\\\\\text{Now,}\\\\y = 2\cdot \dfrac 1 5 \displaystyle \int u^4 ~ du\\\\\\~~=\dfrac 25 \cdot \dfrac{u^{4+1}}{4+1} +C\\\\\\~~=\dfrac 25 \cdot \dfrac{u^5}5+C\\\\\\~~=\dfrac{2u^5}{25}+C\\\\\\~~=\dfrac{2(5x-3)^5}{25}+C$

$\textbf{a)}\\\\y = \displaystyle \int xe^{3x} dx\\\\\text{We know that,}\\\\ \displaystyle \int (uv) ~dx = u \displaystyle \int v ~ dx - \displaystyle \int \left[ \dfrac{du}{dx} \displaystyle \int ~ v ~ dx \right]~ dx\\\\\text{Let}, u =x~ \text{and}~ v=e^{3x} .\\\\y= \displaystyle \int xe^{3x} ~dx\\\\\\~~= x\displaystyle \int e^{3x} ~ dx - \displaystyle \int \left[\dfrac{d}{dx}(x) \displaystyle \int e^{3x}~ dx \right]~ dx\\\\\\$

$=x\displaystyle \int e^{3x}~ dx - \displaystyle \dfrac 13 \int \left(e^{3x} \right)~ dx\\\\\\=\dfrac{xe^{3x}}3 - \dfrac 13 \cdot \dfrac{ e^{3x}}3+C\\\\\\= \dfrac{xe^{3x}}{3}- \dfrac{e^{3x}}{9}+C\\\\\\=\dfrac{3xe^{3x}}{9}- \dfrac{e^{3x}}9 + C\\\\\\= \dfrac 19e^{3x}(3x-1)+C$

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8 0

2 years ago

The population of current statistics students has ages with mean mu and standard deviation sigma. samples of statistics students

hram777 [196]

Answer: The central limit theorem tells us that when random samples are chosen the results tend to approach a normal distribution.

The basic idea is that the more random samples that you select, the closer you should get to the mean. In most cases, 30 or more samples is regarded as a large enough sample to get close to the mean. Our sample is 48, so we should be close to the mean.

3 0

4 years ago

Sole and check 5y + 7 = 14y + 7

mart [117]

$5y + 7 = 14y + 7 \\ \\ 5y = 14y \ / \ cancel \ 7\\ \\ 5y - 14y = 0 \ / \ terms \ to \ one \ side\\ \\ -9y = 0 \ / \ simplify \\ \\ y = 0 \ / \ divide \ by \ -9 \\ \\ CHECK \\ \\ 5y + 7 = 14y + 7 \ / \ let \ y = 0 \\ \\ 5 \times 0 + 7 = 14 \times 0 + 7 \\ \\ Answer: \fbox {y = 0}$

8 0

3 years ago

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There are 330 walnuts in 6 bags. if each bag has the same number of walnuts, how many walnuts are in 2 bags?

miskamm [114]

Well if 330 are divided equally into 6 than that means there are 55 in each bag and together in 2 bags total there would be 110 so your answer is either 55 or 110

5 0

3 years ago

Read 2 more answers