Answer:
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Step-by-step explanation:
Answer:
(a)
The probability that you stop at the fifth flip would be

(b)
The expected numbers of flips needed would be

Therefore, suppose that
, then the expected number of flips needed would be 1/0.5 = 2.
Step-by-step explanation:
(a)
Case 1
Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

Case 2
Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

Therefore the probability that you stop at the fifth flip would be

(b)
The expected numbers of flips needed would be

Therefore, suppose that
, then the expected number of flips needed would be 1/0.5 = 2.
Answer:
True
Step-by-step explanation:
Key idea: the graph of a proportional relationship is a straight line through the origin.