The circumference follows the formula
C= 2 (pi)R
R is the radius which is half the diameter when we put this into the equation we get
C = 2 (pi)(4.5)
C=28.274334
Answer:
No, it is not a right triangle.
Step-by-step explanation:
The simplest way to determine is testing out the numbers with Pythagorian theorem.
If it complies with the theorem, it is a right triangle.
let's assume c = 28, b = 21, and a = 20
the longest side is the hypotenuse so side c (28 in) will be the hypotenuse.
According to the Pythagorian theorem, the square of the length of hypotenuse must equal to the sum of squares of other two sides.
check:
c^2 = 28^2 = 784
a^2 + b^2 = 21^2 + 20^2 = 841
because c^2 is not equal to a^2 + b^2, the triangle is not a right triangle.
1. Rational numbers can be written as a ratio (fraction)
Whole numbers are rational. 5 = 5/1, for example.
Square roots are NOT rational. Example: √3
However, square roots of square numbers can be simplified, and are therefore rational. <span>√4 = 2, rational.</span>
√4 + <span>√16 = 2 + 4 = 6. rational
</span>√5 + √36...<span> irrational
</span>√9 + <span>√24... irrational
</span>2 × <span>√4 = 2 × 2 = 4. rational
</span>√49 × <span>√81 = 7 × 9 = 63. rational
</span>3√12... irrational
2.


3.


4.
![n^\frac1x=\sqrt[x]n](https://tex.z-dn.net/?f=n%5E%5Cfrac1x%3D%5Csqrt%5Bx%5Dn)
![\sqrt[3]{m^2n^5}=m^{\frac23}n^{\frac53}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bm%5E2n%5E5%7D%3Dm%5E%7B%5Cfrac23%7Dn%5E%7B%5Cfrac53%7D)
5.


A, since neither 3 nor 12 is a square but we end up with 6.
Answer:
use a2+b2=c2 so
Step-by-step explanation:
11(squared)+b(squared)=13(squared)
=121+b2=169
-121. -121
b2= 48
square root 48
Side B= 6.928
and then just round 6.928
hope this helped