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oksian1 [2.3K]
3 years ago
11

A rectangle is 32m by 8m is similar to a rectangle 4m by x m. Find the 2 possible values of x .

Mathematics
1 answer:
Stella [2.4K]3 years ago
7 0
<h3>Answers:</h3><h3>x = 1 or x = 16</h3>

======================================

Work Shown:

Draw out a rectangle that is 32 units wide horizontally and 8 units tall vertically.

Then draw out another rectangle that is 4 meters wide horizontally and x meters tall vertically.

The horizontal and vertical sides pair up to form these fractions: 32/4 and 8/x

Set the fractions equal to one another. Solve for x

32/4 = 8/x

32x = 8*4 ... cross multiply

32x = 32  

x = 32/32 ... divide both sides by 32

x = 1

-----------------------

Somewhere else on your paper, draw the same 32 by 8 rectangle to make 32 the horizontal component

Next to this rectangle, draw a rectangle that has x as the horizontal part and 4 as the vertical. Note the swap here.

We now have this equation to solve for

32/x = 8/4

once again, note the swap

Let's solve for x

32/x = 8/4

32*4 = 8*x

128 = 8x

8x = 128

x = 128/8

x = 16

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The table shows the amount of red paint that can be added to different amounts of white paint while making a custom paint color:
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Find the value of x and y (i need this asap please)
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3 years ago
What is the explicit formula of a1=-3,d=2
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Step-by-step explanation:

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The common difference  = 2

In a ARITHMETIC PROGRESSION:

The nth term of a sequence is given as

a(n) =  a + (n-1) d

⇒ Here, a(n)  = -1 + (n-1)(2)

                      = -1 + 2n -2

                       = 2n - 3

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7 0
3 years ago
Which of the following sets could be the sides of a right triangle?
coldgirl [10]

Answer: Choice B) {3, 5, sqrt(34)}

=====================================

Explanation:

We can only have a right triangle if and only if a^2+b^2 = c^2 is a true equation. The 'c' is the longest side, aka hypotenuse. The legs 'a' and 'b' can be in any order you want.

-----------

For choice A,

a = 2

b = 3

c = sqrt(10)

So,

a^2+b^2 = 2^2+3^2 = 4+9 = 13

but

c^2 = (sqrt(10))^2 = 10

which is not equal to 13 from above. Cross choice A off the list.

-----------

Checking choice B

a = 3

b = 5

c = sqrt(34)

Square each equation

a^2 = 3^2 = 9

b^2 = 5^2 = 25

c^2 = (sqrt(34))^2 = 34

We can see that

a^2+b^2 = 9+25 = 34

which is exactly equal to c^2 above. This confirms the answer.

-----------

Let's check choice C

a = 5, b = 8, c = 12

a^2 = 25, b^2 = 64, c^2 = 144

So,

a^2+b^2 = c^2

25+64 = 144

89 = 144

which is a false equation allowing us to cross choice C off the list.

7 0
3 years ago
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