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12345 [234]
3 years ago
12

What is the slope of the line?

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0

Answer:

4/3

Step-by-step explanation:

Slope is rise/run so find two points and find the rise/run. (0,-1) and (4,2) so the slope would be 4/3

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valina [46]

Answer:

solution e. (0,0)______b. (-2,-10)_______c. (5, -12)__________of

2x + 5y < 10

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3 years ago
GIVEN TRIANGLE PQR WITH P(1,6) Q(3,1) AND R(8,3). WHAT POINT BISECTS PQ? B) WHY DO SLOPES OF THE PQ AND QR SHOW THAT M
vfiekz [6]

Answer: I think

GIVEN TRIANGLE PQR WITH P(1,6) Q(3,1) AND R(8,3). WHAT POINT BISECTS PQ? B) WHY DO SLOPES OF THE PQ AND QR SHOW THAT M

Step-by-step explanation:

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3 years ago
Join my among us code <br><br> EDTHOF
PSYCHO15rus [73]

Answer:

BET

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Sonny substituted 5 for x in the proportion startfraction 16 over x endfraction = startfraction 48 over 15 endfraction and cross
frez [133]

The cross products of the proportion are equal.

According to the question, Sonny's equation can be written as follows.

16/x = 48/15

Now, the variable x is replaced by the constant 5. So the equation can now be written as follows.

16/5 = 48/15

When two fractions are equal to one another as shown above, the constants are cross multiplied with one another in order to form an equation.

16*15= 48*5

The values of both the products are equal which is 240.

Therefore, because the cross products of the proportion are equal.

Learn more about Proportion on:

brainly.com/question/1496357

#SPJ4

4 0
2 years ago
Which values are within the range of the piecewise-defined function?
musickatia [10]

Answer:  y < 1

<u>Step-by-step explanation:</u>

\begin{array}{c|c||l}\underline{x; x-3}&\underline{y=-x-2}&\\-3&-(-3)-2=1&\text{approaching but not including 1}\\-2&-(-2)-2=0&\\-1&-(-1)-2=-1&\end{array}

The first function has the range of y < -4

The second function has the range of y = -3

The third function has the range of y < 1

The largest y-value is 1 and the smallest y-value is -∞, therefore the range (y-values) are from -∞ to 1 → y < 1

6 0
3 years ago
Read 2 more answers
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