3 years ago

How do I solve equations like this?

Mathematics

1 answer:

amid [387]3 years ago

7 0

Can u state the problem it is very blurry thx

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Tony has 60$ to buy souvenirs for his grandkids at the baseball game. Pennants cost $7.50 and hats cost $11.99. This relationshi

Step2247 [10]

C. 0<p<3 is the answer (at most)

Hope dis helped :)

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2 years ago

There is a game at the carnival that costs $20 to play. There are two outcomes: either you win $100 , or you lose. To play you r

Taya2010 [7]

Outcome on winning = $100 - $20 = $80
Outcome on losing = $20

Probability of winning = 1/6
Probability of losing = 5/6

Expected Value = 1/6 (80) +5/6(-20) = -3.333

This shows on average from each game, the game earns $ 3.333.

So, if 1000 such games are played, the game will earn 1000 x 3.33 = $3330

So, the answer to this question is option A

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2 years ago

If aerts305 is 16 and his friend is 15 who’s older

Angelina_Jolie [31]

Answer:

aerts is older by 1 year

Step-by-step explanation:

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2 years ago

Write an equation in standard form of the hyperbola described.

marishachu [46]

Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

$\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}$

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2 years ago

2 1/2 divided by 1 7/8 <br> SHOW YOUR WORK and if you do i'll give you brainiest :)

Murljashka [212]

Answer:

1.33

Step-by-step explanation:

2 1/2=2.5

1 7/8=1.87

=1.33

3 0

2 years ago